11352113 has 4 divisors (see below), whose sum is σ = 11358960. Its totient is φ = 11345268.

The previous prime is 11352083. The next prime is 11352151. The reversal of 11352113 is 31125311.

11352113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11352113 - 2⁶ = 11352049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11352091 and 11352100.

It is not an unprimeable number, because it can be changed into a prime (11352163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 806 + ... + 4832.

It is an arithmetic number, because the mean of its divisors is an integer number (2839740).

Almost surely, 2^11352113 is an apocalyptic number.

It is an amenable number.

11352113 is a deficient number, since it is larger than the sum of its proper divisors (6847).

11352113 is an equidigital number, since it uses as much as digits as its factorization.

11352113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6846.

The product of its digits is 90, while the sum is 17.

The square root of 11352113 is about 3369.2896877532. The cubic root of 11352113 is about 224.7461367238.

Adding to 11352113 its reverse (31125311), we get a palindrome (42477424).

The spelling of 11352113 in words is "eleven million, three hundred fifty-two thousand, one hundred thirteen".