Base | Representation |
---|---|
bin | 100001110011100… |
… | …1011111101001101 |
3 | 2221001110202021002 |
4 | 1003213023331031 |
5 | 4310343033221 |
6 | 304320550045 |
7 | 40052532242 |
oct | 10347137515 |
9 | 2831422232 |
10 | 1134346061 |
11 | 532343a92 |
12 | 277a82325 |
13 | 151017bb4 |
14 | aa91d5c9 |
15 | 698bc80b |
hex | 439cbf4d |
1134346061 has 2 divisors, whose sum is σ = 1134346062. Its totient is φ = 1134346060.
The previous prime is 1134346043. The next prime is 1134346193. The reversal of 1134346061 is 1606434311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 773118025 + 361228036 = 27805^2 + 19006^2 .
It is an emirp because it is prime and its reverse (1606434311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134346061 - 230 = 60604237 is a prime.
It is a super-2 number, since 2×11343460612 = 2573481972212431442, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1134346001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567173030 + 567173031.
It is an arithmetic number, because the mean of its divisors is an integer number (567173031).
Almost surely, 21134346061 is an apocalyptic number.
It is an amenable number.
1134346061 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134346061 is an equidigital number, since it uses as much as digits as its factorization.
1134346061 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The square root of 1134346061 is about 33680.0543497186. The cubic root of 1134346061 is about 1042.9140600368.
The spelling of 1134346061 in words is "one billion, one hundred thirty-four million, three hundred forty-six thousand, sixty-one".
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