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113230113 = 337743371
BaseRepresentation
bin1101011111111…
…00000100100001
321220001200111220
412233330010201
5212441330423
615122525253
72543303643
oct657740441
9256050456
10113230113
1158a08507
1231b06829
131a5c6689
1411076893
159e199e3
hex6bfc121

113230113 has 4 divisors (see below), whose sum is σ = 150973488. Its totient is φ = 75486740.

The previous prime is 113230111. The next prime is 113230129. The reversal of 113230113 is 311032311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113230113 - 21 = 113230111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113230092 and 113230101.

It is not an unprimeable number, because it can be changed into a prime (113230111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18871683 + ... + 18871688.

It is an arithmetic number, because the mean of its divisors is an integer number (37743372).

Almost surely, 2113230113 is an apocalyptic number.

It is an amenable number.

113230113 is a deficient number, since it is larger than the sum of its proper divisors (37743375).

113230113 is an equidigital number, since it uses as much as digits as its factorization.

113230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37743374.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 113230113 is about 10640.9639131049. The cubic root of 113230113 is about 483.7867617570.

Adding to 113230113 its reverse (311032311), we get a palindrome (424262424).

The spelling of 113230113 in words is "one hundred thirteen million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 37743371 113230113