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1124412433 is a prime number
BaseRepresentation
bin100001100000101…
…0010110000010001
32220100210001212221
41003001102300101
54300322144213
6303324021041
736602230234
oct10301226021
92810701787
101124412433
11527779781
12274691781
1314bc4a601
14a949541b
1568aa938d
hex43052c11

1124412433 has 2 divisors, whose sum is σ = 1124412434. Its totient is φ = 1124412432.

The previous prime is 1124412427. The next prime is 1124412449. The reversal of 1124412433 is 3342144211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1088208144 + 36204289 = 32988^2 + 6017^2 .

It is a cyclic number.

It is not a de Polignac number, because 1124412433 - 221 = 1122315281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1124412398 and 1124412407.

It is not a weakly prime, because it can be changed into another prime (1124412463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562206216 + 562206217.

It is an arithmetic number, because the mean of its divisors is an integer number (562206217).

Almost surely, 21124412433 is an apocalyptic number.

It is an amenable number.

1124412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124412433 is an equidigital number, since it uses as much as digits as its factorization.

1124412433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 25.

The square root of 1124412433 is about 33532.2595868516. The cubic root of 1124412433 is about 1039.8608150150.

Adding to 1124412433 its reverse (3342144211), we get a palindrome (4466556644).

The spelling of 1124412433 in words is "one billion, one hundred twenty-four million, four hundred twelve thousand, four hundred thirty-three".