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112134113 = 7131232243
BaseRepresentation
bin1101010111100…
…00011111100001
321211000000002022
412223300133201
5212201242423
615043231225
72531060420
oct653603741
9254000068
10112134113
115832a023
1231678515
131a301860
1410c6d2b7
159c9edc8
hex6af07e1

112134113 has 8 divisors (see below), whose sum is σ = 138011328. Its totient is φ = 88721424.

The previous prime is 112134107. The next prime is 112134133. The reversal of 112134113 is 311431211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 112134113 - 210 = 112133089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112134091 and 112134100.

It is not an unprimeable number, because it can be changed into a prime (112134103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 616031 + ... + 616212.

It is an arithmetic number, because the mean of its divisors is an integer number (17251416).

Almost surely, 2112134113 is an apocalyptic number.

112134113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

112134113 is a deficient number, since it is larger than the sum of its proper divisors (25877215).

112134113 is a wasteful number, since it uses less digits than its factorization.

112134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1232263.

The product of its digits is 72, while the sum is 17.

The square root of 112134113 is about 10589.3395922503. The cubic root of 112134113 is about 482.2207757391.

Adding to 112134113 its reverse (311431211), we get a palindrome (423565324).

The spelling of 112134113 in words is "one hundred twelve million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 7 13 91 1232243 8625701 16019159 112134113