Base | Representation |
---|---|
bin | 1101010111100… |
… | …00010000001010 |
3 | 21210222221201220 |
4 | 12223300100022 |
5 | 212201230010 |
6 | 15043222510 |
7 | 2531054514 |
oct | 653602012 |
9 | 253887656 |
10 | 112133130 |
11 | 5832930a |
12 | 31677a36 |
13 | 1a301285 |
14 | 10c6cbb4 |
15 | 9c9e970 |
hex | 6af040a |
112133130 has 32 divisors (see below), whose sum is σ = 271093824. Its totient is φ = 29682816.
The previous prime is 112133123. The next prime is 112133137. The reversal of 112133130 is 31331211.
It is an interprime number because it is at equal distance from previous prime (112133123) and next prime (112133137).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (112133137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9532 + ... + 17751.
It is an arithmetic number, because the mean of its divisors is an integer number (8471682).
Almost surely, 2112133130 is an apocalyptic number.
112133130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112133130 is an abundant number, since it is smaller than the sum of its proper divisors (158960694).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112133130 is a wasteful number, since it uses less digits than its factorization.
112133130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27430.
The product of its (nonzero) digits is 54, while the sum is 15.
The square root of 112133130 is about 10589.2931775449. The cubic root of 112133130 is about 482.2193666395.
Adding to 112133130 its reverse (31331211), we get a palindrome (143464341).
The spelling of 112133130 in words is "one hundred twelve million, one hundred thirty-three thousand, one hundred thirty".
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