111135113 has 2 divisors, whose sum is σ = 111135114. Its totient is φ = 111135112.

The previous prime is 111135109. The next prime is 111135151. The reversal of 111135113 is 311531111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95199049 + 15936064 = 9757^2 + 3992^2 .

It is an emirp because it is prime and its reverse (311531111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111135113 - 2² = 111135109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111135091 and 111135100.

It is not a weakly prime, because it can be changed into another prime (111137113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55567556 + 55567557.

It is an arithmetic number, because the mean of its divisors is an integer number (55567557).

Almost surely, 2^111135113 is an apocalyptic number.

It is an amenable number.

111135113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111135113 is an equidigital number, since it uses as much as digits as its factorization.

111135113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 45, while the sum is 17.

The square root of 111135113 is about 10542.0639819724. The cubic root of 111135113 is about 480.7844709908.

Adding to 111135113 its reverse (311531111), we get a palindrome (422666224).

The spelling of 111135113 in words is "one hundred eleven million, one hundred thirty-five thousand, one hundred thirteen".