11009983 has 2 divisors, whose sum is σ = 11009984. Its totient is φ = 11009982.

The previous prime is 11009959. The next prime is 11009989. The reversal of 11009983 is 38990011.

11009983 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (38990011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11009983 is a prime.

It is a super-3 number, since 3×11009983³ (a number of 22 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11009989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5504991 + 5504992.

It is an arithmetic number, because the mean of its divisors is an integer number (5504992).

Almost surely, 2^11009983 is an apocalyptic number.

11009983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11009983 is an equidigital number, since it uses as much as digits as its factorization.

11009983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 31.

The square root of 11009983 is about 3318.1294429241. The cubic root of 11009983 is about 222.4652674817.

Adding to 11009983 its reverse (38990011), we get a palindrome (49999994).

The spelling of 11009983 in words is "eleven million, nine thousand, nine hundred eighty-three".