10912433 has 4 divisors (see below), whose sum is σ = 12471360. Its totient is φ = 9353508.

The previous prime is 10912427. The next prime is 10912457. The reversal of 10912433 is 33421901.

10912433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33421901 = 71 ⋅470731.

It is a cyclic number.

It is not a de Polignac number, because 10912433 - 2⁴ = 10912417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10912399 and 10912408.

It is not an unprimeable number, because it can be changed into a prime (10912423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 779453 + ... + 779466.

It is an arithmetic number, because the mean of its divisors is an integer number (3117840).

Almost surely, 2^10912433 is an apocalyptic number.

It is an amenable number.

10912433 is a deficient number, since it is larger than the sum of its proper divisors (1558927).

10912433 is an equidigital number, since it uses as much as digits as its factorization.

10912433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1558926.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 10912433 is about 3303.3971907719. The cubic root of 10912433 is about 221.8062928964.

The spelling of 10912433 in words is "ten million, nine hundred twelve thousand, four hundred thirty-three".