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1041433153 is a prime number
BaseRepresentation
bin111110000100110…
…000001001000001
32200120122021201021
4332010300021001
54113101330103
6251201305441
734544015155
oct7604601101
92616567637
101041433153
11494953162
12250935281
131379b6147
149c455065
1561667bbd
hex3e130241

1041433153 has 2 divisors, whose sum is σ = 1041433154. Its totient is φ = 1041433152.

The previous prime is 1041433139. The next prime is 1041433157. The reversal of 1041433153 is 3513341401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931958784 + 109474369 = 30528^2 + 10463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1041433153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1041433157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520716576 + 520716577.

It is an arithmetic number, because the mean of its divisors is an integer number (520716577).

Almost surely, 21041433153 is an apocalyptic number.

It is an amenable number.

1041433153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041433153 is an equidigital number, since it uses as much as digits as its factorization.

1041433153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 1041433153 is about 32271.2434374630. The cubic root of 1041433153 is about 1013.6245788125.

Adding to 1041433153 its reverse (3513341401), we get a palindrome (4554774554).

The spelling of 1041433153 in words is "one billion, forty-one million, four hundred thirty-three thousand, one hundred fifty-three".