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104025137 is a prime number
BaseRepresentation
bin1100011001101…
…00110000110001
321020202000122212
412030310300301
5203112301022
614153341505
72402125166
oct614646061
9236660585
10104025137
11537a0697
122aa07895
1318722948
14db5c06d
1591ec3e2
hex6334c31

104025137 has 2 divisors, whose sum is σ = 104025138. Its totient is φ = 104025136.

The previous prime is 104025107. The next prime is 104025139. The reversal of 104025137 is 731520401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84805681 + 19219456 = 9209^2 + 4384^2 .

It is a cyclic number.

It is not a de Polignac number, because 104025137 - 28 = 104024881 is a prime.

Together with 104025139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104025139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52012568 + 52012569.

It is an arithmetic number, because the mean of its divisors is an integer number (52012569).

Almost surely, 2104025137 is an apocalyptic number.

It is an amenable number.

104025137 is a deficient number, since it is larger than the sum of its proper divisors (1).

104025137 is an equidigital number, since it uses as much as digits as its factorization.

104025137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 104025137 is about 10199.2713955459. The cubic root of 104025137 is about 470.3048226331.

Adding to 104025137 its reverse (731520401), we get a palindrome (835545538).

The spelling of 104025137 in words is "one hundred four million, twenty-five thousand, one hundred thirty-seven".