1032101141 has 2 divisors, whose sum is σ = 1032101142. Its totient is φ = 1032101140.

The previous prime is 1032101131. The next prime is 1032101143. The reversal of 1032101141 is 1411012301.

1032101141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 848498641 + 183602500 = 29129^2 + 13550^2 .

It is an emirp because it is prime and its reverse (1411012301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1032101141 is a prime.

It is a super-3 number, since 3×1032101141³ (a number of 28 digits) contains 333 as substring.

Together with 1032101143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1032101143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516050570 + 516050571.

It is an arithmetic number, because the mean of its divisors is an integer number (516050571).

Almost surely, 2^1032101141 is an apocalyptic number.

It is an amenable number.

1032101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032101141 is an equidigital number, since it uses as much as digits as its factorization.

1032101141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 1032101141 is about 32126.3309607555. The cubic root of 1032101141 is about 1010.5878814544.

Adding to 1032101141 its reverse (1411012301), we get a palindrome (2443113442).

The spelling of 1032101141 in words is "one billion, thirty-two million, one hundred one thousand, one hundred forty-one".