10304113 has 4 divisors (see below), whose sum is σ = 10313460. Its totient is φ = 10294768.

The previous prime is 10304111. The next prime is 10304117. The reversal of 10304113 is 31140301.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31140301 = 967 ⋅32203.

It can be written as a sum of positive squares in 2 ways, for example, as 2334784 + 7969329 = 1528^2 + 2823^2 .

It is a cyclic number.

It is not a de Polignac number, because 10304113 - 2¹ = 10304111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10304093 and 10304102.

It is not an unprimeable number, because it can be changed into a prime (10304111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2758 + ... + 5311.

It is an arithmetic number, because the mean of its divisors is an integer number (2578365).

Almost surely, 2^10304113 is an apocalyptic number.

It is an amenable number.

10304113 is a deficient number, since it is larger than the sum of its proper divisors (9347).

10304113 is an equidigital number, since it uses as much as digits as its factorization.

10304113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9346.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 10304113 is about 3210.0020249215. The cubic root of 10304113 is about 217.6056684766.

Subtracting from 10304113 its sum of digits (13), we obtain a square (10304100 = 3210²).

Adding to 10304113 its reverse (31140301), we get a palindrome (41444414).

The spelling of 10304113 in words is "ten million, three hundred four thousand, one hundred thirteen".