Base | Representation |
---|---|
bin | 1100001010010… |
… | …10100001111011 |
3 | 21002222000012212 |
4 | 12011022201323 |
5 | 202104022042 |
6 | 14042325335 |
7 | 2346063041 |
oct | 605124173 |
9 | 232860185 |
10 | 102017147 |
11 | 52649aa1 |
12 | 2a1b984b |
13 | 1819b99b |
14 | d798391 |
15 | 8e52482 |
hex | 614a87b |
102017147 has 2 divisors, whose sum is σ = 102017148. Its totient is φ = 102017146.
The previous prime is 102017129. The next prime is 102017159. The reversal of 102017147 is 741710201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102017147 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (102017347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51008573 + 51008574.
It is an arithmetic number, because the mean of its divisors is an integer number (51008574).
Almost surely, 2102017147 is an apocalyptic number.
102017147 is a deficient number, since it is larger than the sum of its proper divisors (1).
102017147 is an equidigital number, since it uses as much as digits as its factorization.
102017147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 392, while the sum is 23.
The square root of 102017147 is about 10100.3538056842. The cubic root of 102017147 is about 467.2590532054.
Adding to 102017147 its reverse (741710201), we get a palindrome (843727348).
The spelling of 102017147 in words is "one hundred two million, seventeen thousand, one hundred forty-seven".
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