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1015214131 is a prime number
BaseRepresentation
bin111100100000101…
…111000000110011
32121202022012222101
4330200233000303
54034343323011
6244423321231
734105114651
oct7440570063
92552265871
101015214131
11481075448
12243bb0217
13132436129
1498b8bdd1
155e1d92c1
hex3c82f033

1015214131 has 2 divisors, whose sum is σ = 1015214132. Its totient is φ = 1015214130.

The previous prime is 1015214129. The next prime is 1015214149. The reversal of 1015214131 is 1314125101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1015214131 - 21 = 1015214129 is a prime.

It is a super-2 number, since 2×10152141312 = 2061319463564170322, which contains 22 as substring.

Together with 1015214129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1015214099 and 1015214108.

It is not a weakly prime, because it can be changed into another prime (1015214171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507607065 + 507607066.

It is an arithmetic number, because the mean of its divisors is an integer number (507607066).

Almost surely, 21015214131 is an apocalyptic number.

1015214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1015214131 is an equidigital number, since it uses as much as digits as its factorization.

1015214131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 1015214131 is about 31862.4250646431. The cubic root of 1015214131 is about 1005.0458733382.

Adding to 1015214131 its reverse (1314125101), we get a palindrome (2329339232).

The spelling of 1015214131 in words is "one billion, fifteen million, two hundred fourteen thousand, one hundred thirty-one".