10133117 has 2 divisors, whose sum is σ = 10133118. Its totient is φ = 10133116.

The previous prime is 10133111. The next prime is 10133119. The reversal of 10133117 is 71133101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10023556 + 109561 = 3166^2 + 331^2 .

It is a cyclic number.

It is not a de Polignac number, because 10133117 - 2¹⁰ = 10132093 is a prime.

Together with 10133119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10133095 and 10133104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10133111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066558 + 5066559.

It is an arithmetic number, because the mean of its divisors is an integer number (5066559).

Almost surely, 2^10133117 is an apocalyptic number.

It is an amenable number.

10133117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10133117 is an equidigital number, since it uses as much as digits as its factorization.

10133117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 10133117 is about 3183.2557233122. The cubic root of 10133117 is about 216.3952311649.

Adding to 10133117 its reverse (71133101), we get a palindrome (81266218).

The spelling of 10133117 in words is "ten million, one hundred thirty-three thousand, one hundred seventeen".