1011341281 has 2 divisors, whose sum is σ = 1011341282. Its totient is φ = 1011341280.

The previous prime is 1011341263. The next prime is 1011341321. The reversal of 1011341281 is 1821431101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 843379681 + 167961600 = 29041^2 + 12960^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011341281 - 2⁵ = 1011341249 is a prime.

It is a super-2 number, since 2×1011341281² = 2045622373309441922, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011341231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670640 + 505670641.

It is an arithmetic number, because the mean of its divisors is an integer number (505670641).

Almost surely, 2^1011341281 is an apocalyptic number.

It is an amenable number.

1011341281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011341281 is an equidigital number, since it uses as much as digits as its factorization.

1011341281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

The square root of 1011341281 is about 31801.5924286819. The cubic root of 1011341281 is about 1003.7662247439.

Adding to 1011341281 its reverse (1821431101), we get a palindrome (2832772382).

The spelling of 1011341281 in words is "one billion, eleven million, three hundred forty-one thousand, two hundred eighty-one".