101130119 has 2 divisors, whose sum is σ = 101130120. Its totient is φ = 101130118.

The previous prime is 101130101. The next prime is 101130143. The reversal of 101130119 is 911031101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101130119 - 2⁸ = 101129863 is a prime.

It is a super-2 number, since 2×101130119² = 20454601937908322, which contains 22 as substring.

It is a Chen prime.

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 101130097 and 101130106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101130719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565059 + 50565060.

It is an arithmetic number, because the mean of its divisors is an integer number (50565060).

Almost surely, 2^101130119 is an apocalyptic number.

101130119 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130119 is an equidigital number, since it uses as much as digits as its factorization.

101130119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 17.

The square root of 101130119 is about 10056.3471996546. The cubic root of 101130119 is about 465.9008535471.

The spelling of 101130119 in words is "one hundred one million, one hundred thirty thousand, one hundred nineteen".