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1004023115 = 5351157193
BaseRepresentation
bin111011110110000…
…010110101001011
32120222020122210022
4323312002311023
54024012214430
6243343411055
733611025044
oct7366026513
92528218708
101004023115
11475821477
122402b3a8b
13130018424
14974b78cb
155d2284e5
hex3bd82d4b

1004023115 has 8 divisors (see below), whose sum is σ = 1205191968. Its totient is φ = 802975680.

The previous prime is 1004023103. The next prime is 1004023177. The reversal of 1004023115 is 5113204001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1004023115 - 212 = 1004019019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1004023093 and 1004023102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11042 + ... + 46151.

It is an arithmetic number, because the mean of its divisors is an integer number (150648996).

Almost surely, 21004023115 is an apocalyptic number.

1004023115 is a deficient number, since it is larger than the sum of its proper divisors (201168853).

1004023115 is an equidigital number, since it uses as much as digits as its factorization.

1004023115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60709.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1004023115 is about 31686.3237848760. The cubic root of 1004023115 is about 1001.3392439583.

Adding to 1004023115 its reverse (5113204001), we get a palindrome (6117227116).

The spelling of 1004023115 in words is "one billion, four million, twenty-three thousand, one hundred fifteen".

Divisors: 1 5 3511 17555 57193 285965 200804623 1004023115