100083121 has 4 divisors (see below), whose sum is σ = 100128112. Its totient is φ = 100038132.

The previous prime is 100083119. The next prime is 100083157. The reversal of 100083121 is 121380001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100083121 - 2¹ = 100083119 is a prime.

It is a super-2 number, since 2×100083121² = 20033262218201282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100083095 and 100083104.

It is not an unprimeable number, because it can be changed into a prime (100083101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18975 + ... + 23668.

It is an arithmetic number, because the mean of its divisors is an integer number (25032028).

Almost surely, 2^100083121 is an apocalyptic number.

It is an amenable number.

100083121 is a deficient number, since it is larger than the sum of its proper divisors (44991).

100083121 is an equidigital number, since it uses as much as digits as its factorization.

100083121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44990.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 100083121 is about 10004.1551867212. The cubic root of 100083121 is about 464.2874522471.

The spelling of 100083121 in words is "one hundred million, eighty-three thousand, one hundred twenty-one".