18490117 has 2 divisors, whose sum is σ = 18490118. Its totient is φ = 18490116.

The previous prime is 18490111. The next prime is 18490123. The reversal of 18490117 is 71109481.

It is a balanced prime because it is at equal distance from previous prime (18490111) and next prime (18490123).

It can be written as a sum of positive squares in only one way, i.e., 13535041 + 4955076 = 3679^2 + 2226^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-18490117 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (18490111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9245058 + 9245059.

It is an arithmetic number, because the mean of its divisors is an integer number (9245059).

Almost surely, 2^18490117 is an apocalyptic number.

It is an amenable number.

18490117 is a deficient number, since it is larger than the sum of its proper divisors (1).

18490117 is an equidigital number, since it uses as much as digits as its factorization.

18490117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 31.

The square root of 18490117 is about 4300.0136046296. The cubic root of 18490117 is about 264.4315189892.

Adding to 18490117 its reverse (71109481), we get a palindrome (89599598).

The spelling of 18490117 in words is "eighteen million, four hundred ninety thousand, one hundred seventeen".