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16398131 is a prime number
BaseRepresentation
bin111110100011…
…011100110011
31010212010000012
4332203130303
513144220011
61343245135
7256244651
oct76433463
933763005
1016398131
119290182
1255a97ab
133521b49
14226bdd1
15168da8b
hexfa3733

16398131 has 2 divisors, whose sum is σ = 16398132. Its totient is φ = 16398130.

The previous prime is 16398119. The next prime is 16398133. The reversal of 16398131 is 13189361.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16398131 - 210 = 16397107 is a prime.

It is a super-2 number, since 2×163981312 = 537797400586322, which contains 22 as substring.

Together with 16398133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16398133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8199065 + 8199066.

It is an arithmetic number, because the mean of its divisors is an integer number (8199066).

Almost surely, 216398131 is an apocalyptic number.

16398131 is a deficient number, since it is larger than the sum of its proper divisors (1).

16398131 is an equidigital number, since it uses as much as digits as its factorization.

16398131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 32.

The square root of 16398131 is about 4049.4605813614. The cubic root of 16398131 is about 254.0571667471.

The spelling of 16398131 in words is "sixteen million, three hundred ninety-eight thousand, one hundred thirty-one".