163314131 has 2 divisors, whose sum is σ = 163314132. Its totient is φ = 163314130.

The previous prime is 163314119. The next prime is 163314133. The reversal of 163314131 is 131413361.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 163314131 - 2¹⁴ = 163297747 is a prime.

It is a super-2 number, since 2×163314131² = 53343010768570322, which contains 22 as substring.

Together with 163314133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 163314097 and 163314106.

It is not a weakly prime, because it can be changed into another prime (163314133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81657065 + 81657066.

It is an arithmetic number, because the mean of its divisors is an integer number (81657066).

Almost surely, 2^163314131 is an apocalyptic number.

163314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

163314131 is an equidigital number, since it uses as much as digits as its factorization.

163314131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 23.

The square root of 163314131 is about 12779.4417327206. The cubic root of 163314131 is about 546.6062436109.

Adding to 163314131 its reverse (131413361), we get a palindrome (294727492).

The spelling of 163314131 in words is "one hundred sixty-three million, three hundred fourteen thousand, one hundred thirty-one".