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154424113 = 314981423
BaseRepresentation
bin10010011010001…
…01001100110001
3101202120120001121
421031011030301
5304013032423
623153502241
73553404034
oct1115051461
9352516047
10154424113
117a194138
1243871981
1325cba81c
141671b01b
15d85545d
hex9345331

154424113 has 4 divisors (see below), whose sum is σ = 159405568. Its totient is φ = 149442660.

The previous prime is 154424099. The next prime is 154424119. The reversal of 154424113 is 311424451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311424451 = 1323955727.

It is a cyclic number.

It is not a de Polignac number, because 154424113 - 221 = 152326961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (154424119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2490681 + ... + 2490742.

It is an arithmetic number, because the mean of its divisors is an integer number (39851392).

Almost surely, 2154424113 is an apocalyptic number.

It is an amenable number.

154424113 is a deficient number, since it is larger than the sum of its proper divisors (4981455).

154424113 is an equidigital number, since it uses as much as digits as its factorization.

154424113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4981454.

The product of its digits is 1920, while the sum is 25.

The square root of 154424113 is about 12426.7498968958. The cubic root of 154424113 is about 536.5024445551.

Adding to 154424113 its reverse (311424451), we get a palindrome (465848564).

The spelling of 154424113 in words is "one hundred fifty-four million, four hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 31 4981423 154424113