15122113 has 4 divisors (see below), whose sum is σ = 15378480. Its totient is φ = 14865748.

The previous prime is 15122089. The next prime is 15122117. The reversal of 15122113 is 31122151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31122151 = 23 ⋅1353137.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15122113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15122117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128095 + ... + 128212.

It is an arithmetic number, because the mean of its divisors is an integer number (3844620).

Almost surely, 2^15122113 is an apocalyptic number.

It is an amenable number.

15122113 is a deficient number, since it is larger than the sum of its proper divisors (256367).

15122113 is an equidigital number, since it uses as much as digits as its factorization.

15122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 256366.

The product of its digits is 60, while the sum is 16.

The square root of 15122113 is about 3888.7161120349. The cubic root of 15122113 is about 247.2886363354.

Adding to 15122113 its reverse (31122151), we get a palindrome (46244264).

The spelling of 15122113 in words is "fifteen million, one hundred twenty-two thousand, one hundred thirteen".