141344017 has 4 divisors (see below), whose sum is σ = 141421120. Its totient is φ = 141266916.

The previous prime is 141343997. The next prime is 141344081. The reversal of 141344017 is 710443141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 710443141 = 17 ⋅41790773.

It is a cyclic number.

It is not a de Polignac number, because 141344017 - 2²⁷ = 7126289 is a prime.

It is a super-2 number, since 2×141344017² = 39956262283392578, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141343982 and 141344000.

It is not an unprimeable number, because it can be changed into a prime (141348017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35733 + ... + 39490.

It is an arithmetic number, because the mean of its divisors is an integer number (35355280).

Almost surely, 2^141344017 is an apocalyptic number.

It is an amenable number.

141344017 is a deficient number, since it is larger than the sum of its proper divisors (77103).

141344017 is an equidigital number, since it uses as much as digits as its factorization.

141344017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77102.

The product of its (nonzero) digits is 1344, while the sum is 25.

The square root of 141344017 is about 11888.8189909679. The cubic root of 141344017 is about 520.9057402453.

Adding to 141344017 its reverse (710443141), we get a palindrome (851787158).

The spelling of 141344017 in words is "one hundred forty-one million, three hundred forty-four thousand, seventeen".