Base | Representation |
---|---|
bin | 101011000110011010011 |
3 | 2122202022200 |
4 | 11120303103 |
5 | 330143212 |
6 | 50134243 |
7 | 15001341 |
oct | 5306323 |
9 | 2582280 |
10 | 1412307 |
11 | 8850a6 |
12 | 581383 |
13 | 3a5ab0 |
14 | 28a991 |
15 | 1cd6dc |
hex | 158cd3 |
1412307 has 12 divisors (see below), whose sum is σ = 2197104. Its totient is φ = 869040.
The previous prime is 1412297. The next prime is 1412317. The reversal of 1412307 is 7032141.
It is an interprime number because it is at equal distance from previous prime (1412297) and next prime (1412317).
It is not a de Polignac number, because 1412307 - 28 = 1412051 is a prime.
It is a super-2 number, since 2×14123072 = 3989222124498, which contains 22 as substring.
It is a hoax number, since the sum of its digits (18) coincides with the sum of the digits of its distinct prime factors.
It is an alternating number because its digits alternate between odd and even.
It is a self number, because there is not a number n which added to its sum of digits gives 1412307.
It is not an unprimeable number, because it can be changed into a prime (1412317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5919 + ... + 6152.
It is an arithmetic number, because the mean of its divisors is an integer number (183092).
21412307 is an apocalyptic number.
1412307 is a deficient number, since it is larger than the sum of its proper divisors (784797).
1412307 is a wasteful number, since it uses less digits than its factorization.
1412307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12090 (or 12087 counting only the distinct ones).
The product of its (nonzero) digits is 168, while the sum is 18.
The square root of 1412307 is about 1188.4052339164. The cubic root of 1412307 is about 112.1957408280.
Adding to 1412307 its reverse (7032141), we get a palindrome (8444448).
It can be divided in two parts, 14 and 12307, that added together give a palindrome (12321).
The spelling of 1412307 in words is "one million, four hundred twelve thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.000 sec. • engine limits •