Base | Representation |
---|---|
bin | 110101110101… |
… | …100000100011 |
3 | 222120000010102 |
4 | 311311200203 |
5 | 12103102203 |
6 | 1222253015 |
7 | 230646125 |
oct | 65654043 |
9 | 28500112 |
10 | 14112803 |
11 | 7a6a181 |
12 | 488716b |
13 | 2c01893 |
14 | 1c35215 |
15 | 138b888 |
hex | d75823 |
14112803 has 2 divisors, whose sum is σ = 14112804. Its totient is φ = 14112802.
The previous prime is 14112779. The next prime is 14112811. The reversal of 14112803 is 30821141.
14112803 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14112803 - 212 = 14108707 is a prime.
It is not a weakly prime, because it can be changed into another prime (14112853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056401 + 7056402.
It is an arithmetic number, because the mean of its divisors is an integer number (7056402).
Almost surely, 214112803 is an apocalyptic number.
14112803 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112803 is an equidigital number, since it uses as much as digits as its factorization.
14112803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
The square root of 14112803 is about 3756.7010794046. The cubic root of 14112803 is about 241.6598081816.
Adding to 14112803 its reverse (30821141), we get a palindrome (44933944).
The spelling of 14112803 in words is "fourteen million, one hundred twelve thousand, eight hundred three".
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