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1410444131 is a prime number
BaseRepresentation
bin101010000010001…
…1010101101100011
310122021222222121112
41110010122231203
510342033203011
6351542413535
746644402005
oct12404325543
93567888545
101410444131
11664182608
123344312ab
13196297535
14d5470375
1583c5958b
hex5411ab63

1410444131 has 2 divisors, whose sum is σ = 1410444132. Its totient is φ = 1410444130.

The previous prime is 1410444121. The next prime is 1410444137. The reversal of 1410444131 is 1314440141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1410444131 - 230 = 336702307 is a prime.

It is a super-2 number, since 2×14104441312 = 3978705293344690322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1410444097 and 1410444106.

It is not a weakly prime, because it can be changed into another prime (1410444137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705222065 + 705222066.

It is an arithmetic number, because the mean of its divisors is an integer number (705222066).

Almost surely, 21410444131 is an apocalyptic number.

1410444131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410444131 is an equidigital number, since it uses as much as digits as its factorization.

1410444131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

The square root of 1410444131 is about 37555.8801121742. The cubic root of 1410444131 is about 1121.4638944056.

Adding to 1410444131 its reverse (1314440141), we get a palindrome (2724884272).

The spelling of 1410444131 in words is "one billion, four hundred ten million, four hundred forty-four thousand, one hundred thirty-one".