14080411 has 2 divisors, whose sum is σ = 14080412. Its totient is φ = 14080410.

The previous prime is 14080397. The next prime is 14080421. The reversal of 14080411 is 11408041.

14080411 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11408041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14080411 - 2⁵ = 14080379 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14080421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7040205 + 7040206.

It is an arithmetic number, because the mean of its divisors is an integer number (7040206).

Almost surely, 2^14080411 is an apocalyptic number.

14080411 is a deficient number, since it is larger than the sum of its proper divisors (1).

14080411 is an equidigital number, since it uses as much as digits as its factorization.

14080411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 19.

The square root of 14080411 is about 3752.3873733931. The cubic root of 14080411 is about 241.4747790032.

Adding to 14080411 its reverse (11408041), we get a palindrome (25488452).

The spelling of 14080411 in words is "fourteen million, eighty thousand, four hundred eleven".