14012111 has 2 divisors, whose sum is σ = 14012112. Its totient is φ = 14012110.

The previous prime is 14012081. The next prime is 14012137. The reversal of 14012111 is 11121041.

It is a strong prime.

It is an emirp because it is prime and its reverse (11121041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14012111 - 2¹⁰ = 14011087 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14012092 and 14012101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14012161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006055 + 7006056.

It is an arithmetic number, because the mean of its divisors is an integer number (7006056).

Almost surely, 2^14012111 is an apocalyptic number.

14012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012111 is an equidigital number, since it uses as much as digits as its factorization.

14012111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

The square root of 14012111 is about 3743.2754373677. The cubic root of 14012111 is about 241.0837045606.

Adding to 14012111 its reverse (11121041), we get a palindrome (25133152).

The spelling of 14012111 in words is "fourteen million, twelve thousand, one hundred eleven".