1400050113 has 64 divisors (see below), whose sum is σ = 2472560640. Its totient is φ = 682214400.

The previous prime is 1400050109. The next prime is 1400050129. The reversal of 1400050113 is 3110500041.

It is not a de Polignac number, because 1400050113 - 2² = 1400050109 is a prime.

It is a super-2 number, since 2×1400050113² = 3920280637822625538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400050092 and 1400050101.

It is not an unprimeable number, because it can be changed into a prime (1400050133) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2124178 + ... + 2124836.

It is an arithmetic number, because the mean of its divisors is an integer number (38633760).

Almost surely, 2^1400050113 is an apocalyptic number.

It is an amenable number.

1400050113 is a deficient number, since it is larger than the sum of its proper divisors (1072510527).

1400050113 is a wasteful number, since it uses less digits than its factorization.

1400050113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1238.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1400050113 is about 37417.2435248777. The cubic root of 1400050113 is about 1118.7022897457.

Adding to 1400050113 its reverse (3110500041), we get a palindrome (4510550154).

The spelling of 1400050113 in words is "one billion, four hundred million, fifty thousand, one hundred thirteen".