# Greetings from The On-Line Encyclopedia of Integer Sequences! http://oeis.org/ Search: id:a159469 Showing 1-1 of 1 %I A159469 #52 Feb 21 2020 20:07:41 %S A159469 6,8,20,24,42,48,72,80,110,120,156,168,210,224,272,288,342,360,420, %T A159469 440,506,528,600,624,702,728,812,840,930,960,1056,1088,1190,1224,1332, %U A159469 1368,1482,1520,1640,1680,1806,1848,1980,2024,2162,2208,2352,2400,2550,2600 %N A159469 Maximum remainder when (k + 1)^n + (k - 1)^n is divided by k^2 for variable n and k > 2. %H A159469 Iain Fox, Table of n, a(n) for n = 3..10000 %H A159469 Project Euler, Problem 120: Square remainders %H A159469 Iain Fox, Proof for recursive definition and generating function %H A159469 Index entries for linear recurrences with constant coefficients, signature (1,2,-2,-1,1). %F A159469 maxr(n) = n*n - 2*n if n is even, and n*n - n if n is odd. %F A159469 G.f.: x^3*(-6-2*x)/((x+1)^2*(x-1)^3). - Maksym Voznyy (voznyy(AT)mail.ru), Jul 26 2009 (proved by _Iain Fox_, Nov 26 2017) %F A159469 a(n) = 2*A050187(n). - _R. J. Mathar_, Aug 08 2009 (proved by _Iain Fox_, Nov 27 2017) %F A159469 a(n) = a(n-1) + 2*a(n-2) - 2*a(n-3) - a(n-4) + a(n-5) for n > 7. - _Colin Barker_, Oct 29 2017 (proved by _Iain Fox_, Nov 26 2017) %F A159469 a(n) = n^2 - n*(3 + (-1)^n)/2. - _Iain Fox_, Nov 26 2017 %F A159469 From _Iain Fox_, Nov 27 2017: (Start) %F A159469 a(n) = A000290(n) - A022998(n). %F A159469 a(n) = 2*A093005(n-2) + A168273(n-1). %F A159469 a(n) = (4*(A152749(n-2)) + A091574(n-1) - A010719(n-1))/3. %F A159469 E.g.f.: x*(exp(x)*x - sinh(x)). %F A159469 (End) %e A159469 For n = 3, maxr => 3*3 - 3 = 6 since 3 is odd. %e A159469 For n = 4, maxr => 4*4 - 2*4 = 8 since 4 is even. %t A159469 LinearRecurrence[{1,2,-2,-1,1},{6,8,20,24,42},50] (* _Harvey P. Dale_, Apr 18 2018 *) %o A159469 (PARI) a(n) = if (n % 2, n^2 - n, n^2 - 2*n); \\ _Michel Marcus_, Aug 26 2013 %o A159469 (PARI) first(n) = Vec(x^3*(-6-2*x)/((x+1)^2*(x-1)^3) + O(x^(n+3))) \\ _Iain Fox_, Nov 26 2017 %Y A159469 Cf. A050187. %K A159469 nonn,easy %O A159469 3,1 %A A159469 _Gaurav Kumar_, Apr 13 2009 # Content is available under The OEIS End-User License Agreement: http://oeis.org/LICENSE