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%I A030423 #4 Mar 30 2012 18:56:18
%S A030423 1,1,1,2,3,3,2,2,3,4,5,6,6,5,5,5,6,6,7,8,8,9,9,10,9,8,8,8,8,9,10,11,
%T A030423 11,11,12,12,13,13,12,12,12,12,13,13,13,14,14,13,13,13,14,14,14,13,14,
%U A030423 14,13,14,13,12,13,14,15,16,17,17,17,18,18,18
%N A030423 a(n)=(# 1's)-(# 0's) in first n terms of A030413.
%K A030423 nonn
%O A030423 1,4
%A A030423 _Clark Kimberling_

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