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%I A001109 M4217 N1760 #612 Nov 05 2024 15:22:42
%S A001109 0,1,6,35,204,1189,6930,40391,235416,1372105,7997214,46611179,
%T A001109 271669860,1583407981,9228778026,53789260175,313506783024,
%U A001109 1827251437969,10650001844790,62072759630771,361786555939836,2108646576008245,12290092900109634,71631910824649559,417501372047787720
%N A001109 a(n)^2 is a triangular number: a(n) = 6*a(n-1) - a(n-2) with a(0)=0, a(1)=1.
%C A001109 8*a(n)^2 + 1 = 8*A001110(n) + 1 = A055792(n+1) is a perfect square. - _Gregory V. Richardson_, Oct 05 2002
%C A001109 For n >= 2, A001108(n) gives exactly the positive integers m such that 1,2,...,m has a perfect median. The sequence of associated perfect medians is the present sequence. Let a_1,...,a_m be an (ordered) sequence of real numbers, then a term a_k is a perfect median if Sum_{j=1..k-1} a_j = Sum_{j=k+1..m} a_j. See Puzzle 1 in MSRI Emissary, Fall 2005. - _Asher Auel_, Jan 12 2006
%C A001109 (a(n), b(n)) where b(n) = A082291(n) are the integer solutions of the equation 2*binomial(b,a) = binomial(b+2,a). - Klaus Strassburger (strass(AT)ddfi.uni-duesseldorf.de); comment revised by _Michael Somos_, Apr 07 2003
%C A001109 This sequence gives the values of y in solutions of the Diophantine equation x^2 - 8y^2 = 1. It also gives the values of the product xy where (x,y) satisfies x^2 - 2y^2 = +-1, i.e., a(n) = A001333(n)*A000129(n). a(n) also gives the inradius r of primitive Pythagorean triangles having legs whose lengths are consecutive integers, with corresponding semiperimeter s = a(n+1) = {A001652(n) + A046090(n) + A001653(n)}/2 and area rs = A029549(n) = 6*A029546(n). - _Lekraj Beedassy_, Apr 23 2003 [edited by _Jon E. Schoenfield_, May 04 2014]
%C A001109 n such that 8*n^2 = floor(sqrt(8)*n*ceiling(sqrt(8)*n)). - _Benoit Cloitre_, May 10 2003
%C A001109 For n > 0, ratios a(n+1)/a(n) may be obtained as convergents to continued fraction expansion of 3+sqrt(8): either successive convergents of [6;-6] or odd convergents of [5;1, 4]. - _Lekraj Beedassy_, Sep 09 2003
%C A001109 a(n+1) + A053141(n) = A001108(n+1). Generating floretion: - 2'i + 2'j - 'k + i' + j' - k' + 2'ii' - 'jj' - 2'kk' + 'ij' + 'ik' + 'ji' + 'jk' - 2'kj' + 2e ("jes" series). - _Creighton Dement_, Dec 16 2004
%C A001109 Kekulé numbers for certain benzenoids (see the Cyvin-Gutman reference). - _Emeric Deutsch_, Jun 19 2005
%C A001109 Number of D steps on the line y=x in all Delannoy paths of length n (a Delannoy path of length n is a path from (0,0) to (n,n), consisting of steps E=(1,0), N=(0,1) and D=(1,1)). Example: a(2)=6 because in the 13 (=A001850(2)) Delannoy paths of length 2, namely (DD), (D)NE, (D)EN, NE(D), NENE, NEEN, NDE, NNEE, EN(D), ENNE, ENEN, EDN and EENN, we have altogether six D steps on the line y=x (shown between parentheses). - _Emeric Deutsch_, Jul 07 2005
%C A001109 Define a T-circle to be a first-quadrant circle with integral radius that is tangent to the x- and y-axes. Such a circle has coordinates equal to its radius. Let C(0) be the T-circle with radius 1. Then for n > 0, define C(n) to be the smallest T-circle that does not intersect C(n-1). C(n) has radius a(n+1). Cf. A001653. - _Charlie Marion_, Sep 14 2005
%C A001109 Numbers such that there is an m with t(n+m)=2t(m), where t(n) are the triangular numbers A000217. For instance, t(20)=2*t(14)=210, so 6 is in the sequence. - _Floor van Lamoen_, Oct 13 2005
%C A001109 One half the bisection of the Pell numbers (A000129). - _Franklin T. Adams-Watters_, Jan 08 2006
%C A001109 Pell trapezoids: for n > 0, a(n) = (A000129(n-1)+A000129(n+1))*A000129(n)/2; see also A084158. - _Charlie Marion_, Apr 01 2006
%C A001109 Tested for 2 < p < 27: If and only if 2^p - 1 (the Mersenne number M(p)) is prime then M(p) divides a(2^(p-1)). - _Kenneth J Ramsey_, May 16 2006
%C A001109 If 2^p - 1 is prime then M(p) divides a(2^(p-1)-1). - _Kenneth J Ramsey_, Jun 08 2006; comment corrected by _Robert Israel_, Mar 18 2007
%C A001109 If 8*n+5 and 8*n+7 are twin primes then their product divides a(4*n+3). - _Kenneth J Ramsey_, Jun 08 2006
%C A001109 If p is an odd prime, then if p == 1 or 7 (mod 8), then a((p-1)/2) == 0 (mod p) and a((p+1)/2) == 1 (mod p); if p == 3 or 5 (mod 8), then a((p-1)/2) == 1 (mod p) and a((p+1)/2) == 0 (mod p). _Kenneth J Ramsey_'s comment about twin primes follows from this. - _Robert Israel_, Mar 18 2007
%C A001109 a(n)*(a(n+b) - a(b-2)) = (a(n+1)+1)*(a(n+b-1) - a(b-1)). This identity also applies to any series a(0) = 0 a(1) = 1 a(n) = b*a(n-1) - a(n-2). - _Kenneth J Ramsey_, Oct 17 2007
%C A001109 For n < 0, let a(n) = -a(-n). Then (a(n+j) + a(k+j)) * (a(n+b+k+j) - a(b-j-2)) = (a(n+j+1) + a(k+j+1)) * (a(n+b+k+j-1) - a(b-j-1)). - _Charlie Marion_, Mar 04 2011
%C A001109 Sequence gives y values of the Diophantine equation: 0+1+2+...+x = y^2. If (a,b) and (c,d) are two consecutive solutions of the Diophantine equation: 0+1+2+...+x = y^2 with a<c then a+b = c-d and ((d+b)^2, d^2-b^2) is a solution too. If (a,b), (c,d) and (e,f) are three consecutive solutions of the Diophantine equation 0+1+2+...+x = y^2 with a < c < e then (8*d^2, d*(f-b)) is a solution too. - _Mohamed Bouhamida_, Aug 29 2009
%C A001109 If (p,q) and (r,s) are two consecutive solutions of the Diophantine equation: 0+1+2+...+x = y^2 with p < r then r = 3*p+4*q+1 and s = 2*p+3*q+1. - _Mohamed Bouhamida_, Sep 02 2009
%C A001109 a(n)/A002315(n) converges to cos^2(Pi/8) (see A201488). - _Gary Detlefs_, Nov 25 2009
%C A001109 Binomial transform of A086347. - _Johannes W. Meijer_, Aug 01 2010
%C A001109 If x=a(n), y=A055997(n+1) and z = x^2+y, then x^4 + y^3 = z^2. - _Bruno Berselli_, Aug 24 2010
%C A001109 In general, if b(0)=1, b(1)=k and for n > 1, b(n) = 6*b(n-1) - b(n-2), then
%C A001109   for n > 0, b(n) = a(n)*k-a(n-1); e.g.,
%C A001109   for k=2, when b(n) = A038725(n), 2 = 1*2 - 0, 11 = 6*2 - 1,  64 = 35*2 - 6, 373 = 204*2 - 35;
%C A001109   for k=3, when b(n) = A001541(n), 3 = 1*3 - 0, 17 = 6*3 - 1;  99 = 35*3 - 6; 577 = 204*3 - 35;
%C A001109   for k=4, when b(n) = A038723(n), 4 = 1*4 - 0, 23 = 6*4 - 1; 134 = 35*4 - 6; 781 = 204*4 - 35;
%C A001109   for k=5, when b(n) = A001653(n), 5 = 1*5 - 0, 29 = 6*5 - 1; 169 = 35*5 - 6; 985 = 204*5 - 35.
%C A001109   See also A002315, A054488, A038761, A054489, A054490.
%C A001109   - _Charlie Marion_, Dec 08 2010
%C A001109 See a _Wolfdieter Lang_ comment on A001653 on a sequence of (u,v) values for Pythagorean triples (x,y,z) with x=|u^2-v^2|, y=2*u*v and z=u^2+v^2, with u odd and v even, generated from (u(0)=1,v(0)=2), the triple (3,4,5), by a substitution rule given there. The present a(n) appears there as b(n). The corresponding generated triangles have catheti differing by one length unit. - _Wolfdieter Lang_, Mar 06 2012
%C A001109 a(n)*a(n+2k) + a(k)^2 and a(n)*a(n+2k+1) + a(k)*a(k+1) are triangular numbers. Generalizes description of sequence. - _Charlie Marion_, Dec 03 2012
%C A001109 a(n)*a(n+2k) + a(k)^2 is the triangular square A001110(n+k). a(n)*a(n+2k+1) + a(k)*a(k+1) is the triangular oblong A029549(n+k). - _Charlie Marion_, Dec 05 2012
%C A001109 From _Richard R. Forberg_, Aug 30 2013: (Start)
%C A001109 The squares of a(n) are the result of applying triangular arithmetic to the squares, using A001333 as the "guide" on what integers to square, as follows:
%C A001109 a(2n)^2 = A001333(2n)^2 * (A001333(2n)^2 - 1)/2;
%C A001109 a(2n+1)^2 = A001333(2n+1)^2 * (A001333(2n+1)^2 + 1)/2. (End)
%C A001109 For n >= 1, a(n) equals the number of 01-avoiding words of length n-1 on alphabet {0,1,...,5}. - _Milan Janjic_, Jan 25 2015
%C A001109 Panda and Rout call these "balancing numbers" and note that the period of the sequence modulo a prime p is the same as that modulo p^2 when p = 13, 31, 1546463. But these are precisely the p in A238736 such that p^2 divides A000129(p - (2/p)), where (2/p) is a Jacobi symbol. In light of the above observation by _Franklin T. Adams-Watters_ that the present sequence is one half the bisection of the Pell numbers, i.e., a(n) = A000129(2*n)/2, it follows immediately that modulo a fixed prime p, or any power thereof, the period of a(n) is half that of A000129(n). - _John Blythe Dobson_, Mar 06 2015
%C A001109 The triangular number = square number identity Tri((T(n, 3) - 1)/2) = S(n-1, 6)^2 with Tri, T, and S given in A000217, A053120 and A049310, is the special case k = 1 of the k-family of identities Tri((T(n, 2*k+1) - 1)/2) = Tri(k)*S(n-1, 2*(2*k+1))^2, k >= 0, n >= 0, with S(-1, x) = 0. For k=2 see A108741(n) for S(n-1, 10)^2. This identity boils down to the identities S(n-1, 2*x)^2 = (T(2*n, x) - 1)/(2*(x^2-1)) and  2*T(n, x)^2 - 1 = T(2*n, x) with x = 2*k+1. - _Wolfdieter Lang_, Feb 01 2016
%C A001109 a(2)=6 is perfect. For n=2*k, k > 0, k not equal to 1, a(n) is a multiple of a(2) and since every multiple (beyond 1) of a perfect number is abundant, then a(n) is abundant. sigma(a(4)) = 504 > 408 = 2*a(4). For n=2*k+1, k > 0, a(n) mod 10 = A000012(n), so a(n) is odd. If a(n) is a prime number, it is deficient; otherwise a(n) has one or two distinct prime factors and is therefore deficient again. So for n=2k+1, k > 0, a(n) is deficient. sigma(a(5)) = 1260 < 2378 = 2*a(5). - _Muniru A Asiru_, Apr 14 2016
%C A001109 Behera & Panda call these the balancing numbers, and A001541 are the balancers. - _Michel Marcus_, Nov 07 2017
%C A001109 In general, a second-order linear recurrence with constant coefficients having a signature of (c,d) will be duplicated by a third-order recurrence having a signature of (x,c^2-c*x+d,-d*x+c*d). The formulas of Olivares and Bouhamida in the formula section which have signatures of (7,-7,1) and (5,5,-1), respectively, are specific instances of this general rule for x = 7 and x = 5. - _Gary Detlefs_, Jan 29 2021
%C A001109 Note that 6 is the largest triangular number in the sequence, because it is proved that 8 and 9 are the largest perfect powers which are consecutive (Catalan's conjecture). 0 and 1 are also in the sequence because they are also perfect powers and 0*1/2 = 0^2 and 8*9/2 = (2*3)^2. - _Metin Sariyar_, Jul 15 2021
%D A001109 Julio R. Bastida, Quadratic properties of a linearly recurrent sequence. Proceedings of the Tenth Southeastern Conference on Combinatorics, Graph Theory and Computing (Florida Atlantic Univ., Boca Raton, Fla., 1979), pp. 163--166, Congress. Numer., XXIII-XXIV, Utilitas Math., Winnipeg, Man., 1979. MR0561042 (81e:10009) - From _N. J. A. Sloane_, May 30 2012
%D A001109 A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, pp. 193, 197.
%D A001109 D. M. Burton, The History of Mathematics, McGraw Hill, (1991), p. 213.
%D A001109 L. E. Dickson, History of the Theory of Numbers. Carnegie Institute Public. 256, Washington, DC, Vol. 1, 1919; Vol. 2, 1920; Vol. 3, 1923, see vol. 2, p. 10.
%D A001109 P. Franklin, E. F. Beckenbach, H. S. M Coxeter, N. H. McCoy, K. Menger, and J. L. Synge, Rings And Ideals, No 8, The Carus Mathematical Monographs, The Mathematical Association of America, (1967), pp. 144-146.
%D A001109 A. Patra, G. K. Panda, and T. Khemaratchatakumthorn. "Exact divisibility by powers of the balancing and Lucas-balancing numbers." Fibonacci Quart., 59:1 (2021), 57-64; see B(n).
%D A001109 N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
%D A001109 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
%D A001109 P.-F. Teilhet, Query 2376, L'Intermédiaire des Mathématiciens, 11 (1904), 138-139. - _N. J. A. Sloane_, Mar 08 2022
%H A001109 Indranil Ghosh, <a href="/A001109/b001109.txt">Table of n, a(n) for n = 0..1304</a> (terms 0..200 from T. D. Noe)
%H A001109 Marco Abrate, Stefano Barbero, Umberto Cerruti, and Nadir Murru, <a href="https://www.emis.de/journals/INTEGERS/papers/p38/p38.Abstract.html">Polynomial sequences on quadratic curves</a>, Integers, Vol. 15, 2015, #A38.
%H A001109 Irving Adler, <a href="http://www.fq.math.ca/Scanned/7-2/adler.pdf">Three Diophantine equations - Part II</a>, Fib. Quart., 7 (1969), pp. 181-193.
%H A001109 Seyed Hassan Alavi, Ashraf Daneshkhah, and Cheryl E. Praeger, <a href="https://arxiv.org/abs/2004.04535">Symmetries of biplanes</a>, arXiv:2004.04535 [math.GR], 2020. See v_n in Lemma 7.9 p. 21.
%H A001109 Jean-Paul Allouche, <a href="https://doi.org/10.1051/epjconf/202024401008">Zeta-regularization of arithmetic sequences</a>, EPJ Web of Conferences (2020) Vol. 244, 01008.
%H A001109 Dario Alpern for Diophantine equation <a href="https://www.alpertron.com.ar/SUMPOWER.HTM#4_3_2">a^4+b^3=c^2</a>.
%H A001109 Kasper Andersen, Lisa Carbone, and D. Penta, <a href="https://pdfs.semanticscholar.org/8f0c/c3e68d388185129a56ed73b5d21224659300.pdf">Kac-Moody Fibonacci sequences, hyperbolic golden ratios, and real quadratic fields</a>, Journal of Number Theory and Combinatorics, Vol 2, No. 3 pp 245-278, 2011. See Section 9.
%H A001109 Francesca Arici and Jens Kaad, <a href="https://arxiv.org/abs/2012.11186">Gysin sequences and SU(2)-symmetries of C*-algebras</a>, arXiv:2012.11186 [math.OA], 2020.
%H A001109 Muniru A. Asiru, <a href="http://dx.doi.org/10.1080/0020739X.2016.1164346">All square chiliagonal numbers</a>, International Journal of Mathematical Education in Science and Technology, Volume 47, 2016 - Issue 7.
%H A001109 Jeremiah Bartz, Bruce Dearden, and Joel Iiams, <a href="https://arxiv.org/abs/1810.07895">Classes of Gap Balancing Numbers</a>, arXiv:1810.07895 [math.NT], 2018.
%H A001109 Jeremiah Bartz, Bruce Dearden, Joel Iiams, and Julia Peterson, <a href="https://doi.org/10.1007/978-3-031-52969-6_32">Powers of Two as Sums of Two Balancing Numbers</a>, Combinatorics, Graph Theory and Computing (SEICCGTC 2021) Springer Proc. Math. Stat., Vol 448, pp. 383-392. See p. 384.
%H A001109 Raymond A. Beauregard and Vladimir A. Dobrushkin, <a href="http://www.jstor.org/stable/10.4169/math.mag.89.5.359">Powers of a Class of Generating Functions</a>, Mathematics Magazine, Volume 89, Number 5, December 2016, pp. 359-363.
%H A001109 A. Behera and G. K. Panda, <a href="https://www.fq.math.ca/Scanned/37-2/behera.pdf">On the Square Roots of Triangular Numbers</a>, Fib. Quart., 37 (1999), pp. 98-105.
%H A001109 Hacène Belbachir, Soumeya Merwa Tebtoub, and László Németh, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL23/Nemeth/nemeth7.html">Ellipse Chains and Associated Sequences</a>, J. Int. Seq., Vol. 23 (2020), Article 20.8.5.
%H A001109 Elwyn Berlekamp and Joe P. Buhler, <a href="https://www.msri.org/attachments/media/news/emissary/EmissaryFall2005.pdf">Puzzle Column</a>, Emissary, MSRI Newsletter, Fall 2005. Problem 1, (6 MB).
%H A001109 Kisan Bhoi and Prasanta Kumar Ray, <a href="https://arxiv.org/abs/2212.06372">On the Diophantine equation Bn1+Bn2=2^a1+2^a2+2^a3</a>, arXiv:2212.06372 [math.NT], 2022.
%H A001109 Daniel Birmajer, Juan B. Gil, and Michael D. Weiner, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL19/Gil/gil6.html">On the Enumeration of Restricted Words over a Finite Alphabet</a>, J. Int. Seq. 19 (2016) # 16.1.3, example 12.
%H A001109 Alexander Bogomolny, <a href="https://www.cut-the-knot.org/do_you_know/triSquare.shtml">There exist triangular numbers that are also squares</a>
%H A001109 John C. Butcher, <a href="https://www.math.auckland.ac.nz/~butcher/miniature/miniature2.html">On Ramanujan, continued Fractions and an interesting number</a>
%H A001109 Paula Catarino, Helena Campos, and Paulo Vasco, <a href="http://ami.ektf.hu/uploads/papers/finalpdf/AMI_45_from11to24.pdf">On some identities for balancing and cobalancing numbers</a>, Annales Mathematicae et Informaticae, 45 (2015) pp. 11-24.
%H A001109 E. K. Çetinalp, N. Yilmaz, and Ö. Deveci, <a href="https://www.emis.de/journals/AUA/pdf/109_1734_9.pdf">The balancing-like sequences in groups</a>, Acta Univ. Apulensis Math. (2023) No. 73, 139-153. See p. 144.
%H A001109 S. J. Cyvin and I. Gutman, <a href="https://doi.org/10.1007/978-3-662-00892-8">Kekulé structures in benzenoid hydrocarbons</a>, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (pp. 301, 302, P_{13}).
%H A001109 Mahadi Ddamulira, <a href="https://hal.archives-ouvertes.fr/hal-02405969">Repdigits as sums of three balancing numbers</a>, Mathematica Slovaca, (2019) hal-02405969.
%H A001109 Tomislav Doslic, <a href="https://dx.doi.org/10.1007/s10910-013-0167-2">Planar polycyclic graphs and their Tutte polynomials</a>, Journal of Mathematical Chemistry, Volume 51, Issue 6, 2013, pp. 1599-1607.
%H A001109 D. B. Eperson, <a href="https://www.jstor.org/stable/3613402">Triangular numbers</a>, Math. Gaz., 47 (1963), 236-237.
%H A001109 Leonhard Euler, <a href="https://scholarlycommons.pacific.edu/euler-works/29/">De solutione problematum diophanteorum per numeros integros</a>, Par. 19.
%H A001109 Sergio Falcon, <a href="https://dx.doi.org/10.4236/am.2014.515216">Relationships between Some k-Fibonacci Sequences</a>, Applied Mathematics, 2014, 5, 2226-2234.
%H A001109 Bernadette Faye, Florian Luca, and Pieter Moree, <a href="https://arxiv.org/abs/1708.03563">On the discriminator of Lucas sequences</a>, arXiv:1708.03563 [math.NT], 2017.
%H A001109 Morgan Fiebig, aBa Mbirika, and Jürgen Spilker, <a href="https://arxiv.org/abs/2408.14632">Period patterns, entry points, and orders in the Lucas sequences: theory and applications</a>, arXiv:2408.14632 [math.NT], 2024. See p. 5.
%H A001109 Rigoberto Flórez, Robinson A. Higuita, and Antara Mukherjee, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL17/Mukherjee/mukh2.html">Alternating Sums in the Hosoya Polynomial Triangle</a>, Article 14.9.5 Journal of Integer Sequences, Vol. 17 (2014).
%H A001109 Aviezri S. Fraenkel, <a href="https://dx.doi.org/10.1016/S0012-365X(00)00138-2">On the recurrence f(m+1)= b(m)*f(m)-f(m-1) and applications</a>, Discrete Mathematics 224 (2000), pp. 273-279.
%H A001109 Robert Frontczak, <a href="https://doi.org/10.12988/ams.2018.87111">A Note on Hybrid Convolutions Involving Balancing and Lucas-Balancing Numbers</a>, Applied Mathematical Sciences, Vol. 12, 2018, No. 25, 1201-1208.
%H A001109 Robert Frontczak, <a href="https://www.m-hikari.com/ijma/ijma-2018/ijma-9-12-2018/p/frontczakIJMA9-12-2018.pdf">Sums of Balancing and Lucas-Balancing Numbers with Binomial Coefficients</a>, International Journal of Mathematical Analysis (2018) Vol. 12, No. 12, 585-594.
%H A001109 Robert Frontczak, <a href="https://doi.org/10.12988/ijma.2019.9211">Powers of Balancing Polynomials and Some Consequences for Fibonacci Sums</a>, International Journal of Mathematical Analysis (2019) Vol. 13, No. 3, 109-115.
%H A001109 Robert Frontczak and Taras Goy, <a href="https://arxiv.org/abs/2007.14048">Additional close links between balancing and Lucas-balancing polynomials</a>, arXiv:2007.14048 [math.NT], 2020.
%H A001109 Robert Frontczak and Taras Goy, <a href="https://arxiv.org/abs/2007.14618">More Fibonacci-Bernoulli relations with and without balancing polynomials</a>, arXiv:2007.14618 [math.NT], 2020.
%H A001109 Robert Frontczak and Taras Goy, <a href="https://arxiv.org/abs/2009.09409">Lucas-Euler relations using balancing and Lucas-balancing polynomials</a>, arXiv:2009.09409 [math.NT], 2020.
%H A001109 Robert Frontczak and Kalika Prasad, <a href="https://doi.org/10.1007/s00009-023-02413-2">Balancing polynomials, Fibonacci numbers and some new series for $\pi$</a>, Mediterranean Journal of Mathematics (2023) Vol. 20, Article number: 207.
%H A001109 Bill Gosper, <a href="https://gosper.org/triangsq.pdf">The Triangular Squares</a>, 2014.
%H A001109 H. Harborth, <a href="https://dx.doi.org/10.1007/978-94-015-7801-1_1">Fermat-like binomial equations</a>, Applications of Fibonacci numbers, Proc. 2nd Int. Conf., San Jose/Ca., August 1986, 1-5 (1988).
%H A001109 Brian Hayes, <a href="https://www.americanscientist.org/libraries/documents/200884115366940-2008-09Hayes.pdf">Calculemus!</a>, American Scientist, 96 (Sep-Oct 2008), 362-366.
%H A001109 Milan Janjic, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL18/Janjic/janjic63.html">On Linear Recurrence Equations Arising from Compositions of Positive Integers</a>, Journal of Integer Sequences, Vol. 18 (2015), Article 15.4.7.
%H A001109 Michael A. Jones, <a href="https://www.jstor.org/stable/10.4169/college.math.j.43.3.212">Proof Without Words: The Square of a Balancing Number Is a Triangular Number</a>, The College Mathematics Journal, Vol. 43, No. 3 (May 2012), p. 212.
%H A001109 Refik Keskin and Olcay Karaatli, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL15/Karaatli/karaatli5.html">Some New Properties of Balancing Numbers and Square Triangular Numbers</a>, Journal of Integer Sequences, Vol. 15 (2012), Article #12.1.4.
%H A001109 Omar Khadir, Kalman Liptai, and Laszlo Szalay, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL13/Szalay/szalay11.html">On the Shifted Product of Binary Recurrences</a>, J. Int. Seq. 13 (2010), 10.6.1.
%H A001109 Tanya Khovanova, <a href="https://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>
%H A001109 Phil Lafer, <a href="https://www.fq.math.ca/Scanned/9-1/lafer.pdf">Discovering the square-triangular numbers</a>, Fib. Quart., 9 (1971), 93-105.
%H A001109 Ioana-Claudia Lazăr, <a href="https://arxiv.org/abs/1904.06555">Lucas sequences in t-uniform simplicial complexes</a>, arXiv:1904.06555 [math.GR], 2019.
%H A001109 Kalman Liptai, <a href="https://www.fq.math.ca/Papers1/42-4/quartliptai04_2004.pdf">Fibonacci Balancing Numbers</a>, Fib. Quart. 42 (4) (2004) 330-340.
%H A001109 Madras College, St Andrews, <a href="https://web.archive.org/web/20190920231615/http://www.madras.fife.sch.uk:80/departments/Mathematics/activities/amazingnofacts/fact017.html">Square Triangular Numbers</a>
%H A001109 aBa Mbirika, Janeè Schrader, and Jürgen Spilker, <a href="https://arxiv.org/abs/2301.05758">Pell and associated Pell braid sequences as GCDs of sums of k consecutive Pell, balancing, and related numbers</a>, arXiv:2301.05758 [math.NT], 2023. See also <a href="https://cs.uwaterloo.ca/journals/JIS/VOL26/Mbirika/mbir5.html">J. Int. Seq.</a> (2023) Vol. 26, Art. 23.6.4.
%H A001109 Roger B. Nelson, <a href="https://www.jstor.org/stable/10.4169/math.mag.89.3.159">Multi-Polygonal Numbers</a>, Mathematics Magazine, Vol. 89, No. 3 (June 2016), pp. 159-164.
%H A001109 G. K. Panda, <a href="https://www.fq.math.ca/Papers1/45-3/panda.pdf">Sequence balancing and cobalancing numbers</a>, Fib. Q., Vol. 45, No. 3 (2007), 265-271. See p. 266.
%H A001109 G. K. Panda and S. S. Rout, <a href="https://dx.doi.org/10.1007/s10474-014-0427-z">Periodicity of Balancing Numbers</a>, Acta Mathematica Hungarica 143 (2014), 274-286.
%H A001109 G. K. Panda and Ravi Kumar Davala, <a href="https://www.fq.math.ca/Papers1/53-3/PandaDavala04232015.pdf">Perfect Balancing Numbers</a>, Fibonacci Quart. 53 (2015), no. 3, 261-264.
%H A001109 Ashish Kumar Pandey and B. K. Sharma, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL26/Pandey/pandey14.html">On Inequalities Related to a Generalized Euler Totient Function and Lucas Sequences</a>, J. Int. Seq. (2023) Vol. 26, Art. 23.8.6.
%H A001109 Poo-Sung Park, <a href="https://www.jstor.org/stable/30044886">Ramanujan's Continued Fraction for a Puzzle</a>, College Mathematics Journal, 2005, 363-365.
%H A001109 Michael Penn, <a href="https://www.youtube.com/watch?v=jMfZ9jRsHSI">Balancing Numbers</a>, Youtube video, 2020.
%H A001109 Robert Phillips, <a href="https://web.archive.org/web/20100713033314/http://www.usca.edu/math/~mathdept/bobp/pdf/polgonal.pdf">Polynomials of the form 1+4ke+4ke^2</a>, 2008.
%H A001109 Simon Plouffe, <a href="https://arxiv.org/abs/0911.4975">Approximations de séries génératrices et quelques conjectures</a>, Dissertation, Université du Québec à Montréal, 1992; arXiv:0911.4975 [math.NT], 2009.
%H A001109 Simon Plouffe, <a href="/A000051/a000051_2.pdf">1031 Generating Functions</a>, Appendix to Thesis, Montreal, 1992
%H A001109 B. Polster and M. Ross, <a href="http://arxiv.org/abs/1503.04658">Marching in squares</a>, arXiv preprint arXiv:1503.04658 [math.HO], 2015.
%H A001109 Kalika Prasad, Munesh Kumari, Ritanjali Mohanty, and Hrishikesh Mahato, <a href="https://doi.org/10.1142/S0219498825503670">Spinor Algebra of k-Balancing and k-Lucas-Balancing Numbers</a>, Journal of Algebra and Its Applications (2024).
%H A001109 Kalika Prasad, Munesh Kumari, and Jagmohan Tanti, <a href="https://doi.org/10.1007/s41478-023-00716-x">Octonions and hyperbolic octonions with the k-balancing and k-Lucas balancing numbers</a>, The Journal of Analysis, (2024), Vol. 32, No. 3, 1281-1296.
%H A001109 Kalika Prasad, Munesh Kumari, and Jagmohan Tanti, <a href="https://doi.org/10.5666/KMJ.2023.63.4.539">Generalized k-balancing and k-Lucas balancing numbers and associated polynomials</a>, Kyungpook Mathematical Journal (2023), Vol. 63, No. 4, 539-550.
%H A001109 Kalika Prasad, Hrishikesh Mahato, and Munesh Kumari, <a href="https://doi.org/10.1007/s40590-023-00510-6">Some properties of r-circulant matrices with k-balancing and k-Lucas balancing numbers</a>, Boletín de la Sociedad Matemática Mexicana (2023), Vol. 29, No. 2, Article no. 44.
%H A001109 Helmut Prodinger, <a href="https://arxiv.org/abs/2008.03916">How to sum powers of balancing numbers efficiently</a>, arXiv:2008.03916 [math.NT], 2020.
%H A001109 Rajesh Ram, <a href="https://web.archive.org/web/20131021224033/http://users.tellurian.net/hsejar/maths/triangle/">Triangle Numbers that are Perfect Squares</a>
%H A001109 K. J. Ramsey, <a href="http://groups.yahoo.com/group/Triangular_and_Fibonacci_Numbers/message/23">Relation of Mersenne Primes To Square Triangular Numbers</a> [edited by K. J. Ramsey, May 14 2011]
%H A001109 Kenneth Ramsay and Andras Erszegi, <a href="/A001109/a001109.txt">Relation of Square Triangular Numbers To Mersenne Primes</a>, digest of 4 messages in Triangular_and_Fibonacci_Numbers Yahoo Group, May 15 - Jun 28, 2006.
%H A001109 Kenneth Ramsey, <a href="http://groups.yahoo.com/group/Triangular_and_Fibonacci_Numbers/message/62">Generalized Proof re Square Triangular Numbers</a>
%H A001109 Kenneth Ramsey, <a href="/A001108/a001108.txt">Generalized Proof re Square Triangular Numbers</a>, digest of 2 messages in Triangular_and_Fibonacci_Numbers Yahoo group, May 27, 2005 - Oct 10, 2011.
%H A001109 Salah E. Rihane, Bernadette Faye, Florian Luca, and Alain Togbe, <a href="https://arxiv.org/abs/1811.03015">An exponential Diophantine equation related to the difference between powers of two consecutive Balancing numbers</a>, arXiv:1811.03015 [math.NT], 2018.
%H A001109 A. Sandhya, <a href="https://www.angelfire.com/ak/ashoksandhya/maths2.html">Puzzle 4: A problem Srinivasa Ramanujan, the famous 20th century Indian Mathematician Solved</a>
%H A001109 Sci.math Newsgroup, <a href="https://web.archive.org/web/20130721085940/http://www.math.niu.edu/~rusin/known-math/98/sq_tri">Square numbers which are triangular</a>
%H A001109 Sci.math Newsgroup, <a href="/A000217/a000217_1.txt">Square numbers which are triangular</a> [Cached copy]
%H A001109 R. A. Sulanke, <a href="https://web.archive.org/web/20180416202341/http://math.boisestate.edu/~sulanke/PAPERS/cutpasteII.pdf">Moments, Narayana numbers and the cut and paste for lattice paths</a>.
%H A001109 R. A. Sulanke, <a href="https://doi.org/10.37236/1385">Bijective recurrences concerning Schroeder paths</a>, Electron. J. Combin. 5 (1998), Research Paper 47, 11 pp.
%H A001109 Soumeya M. Tebtoub, Hacène Belbachir, and László Németh, <a href="https://hal.archives-ouvertes.fr/hal-02918958/document#page=18">Integer sequences and ellipse chains inside a hyperbola</a>, Proceedings of the 1st International Conference on Algebras, Graphs and Ordered Sets (ALGOS 2020), hal-02918958 [math.cs], 17-18.
%H A001109 Ahmet Tekcan, Merve Tayat, and Meltem E. Ozbek, <a href="https://dx.doi.org/10.1155/2014/897834">The diophantine equation 8x^2-y^2+8x(1+t)+(2t+1)^2=0 and t-balancing numbers</a>, ISRN Combinatorics, Volume 2014, Article ID 897834, 5 pages.
%H A001109 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/BinomialCoefficient.html">Binomial coefficient</a>.
%H A001109 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/SquareTriangularNumber.html">Square Triangular Number</a>.
%H A001109 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/TriangularNumber.html">Triangular Number</a>.
%H A001109 Wikipedia, <a href="https://en.wikipedia.org/wiki/Triangular_square_number">Triangular square number</a>
%H A001109 Rick Young, <a href="https://web.archive.org/web/20120818220024/http://www.cob.ohio-state.edu/~young_53/Quote.ram.html">Relevant quotation from biography of Ramanujan</a>
%H A001109 <a href="/index/Ch#Cheby">Index entries for sequences related to Chebyshev polynomials.</a>
%H A001109 <a href="/index/Tu#2wis">Index entries for two-way infinite sequences</a>
%H A001109 <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (6,-1).
%F A001109 G.f.: x / (1 - 6*x + x^2). - _Simon Plouffe_ in his 1992 dissertation.
%F A001109 a(n) = S(n-1, 6) = U(n-1, 3) with U(n, x) Chebyshev's polynomials of the second kind. S(-1, x) := 0. Cf. triangle A049310 for S(n, x).
%F A001109 a(n) = sqrt(A001110(n)).
%F A001109 a(n) = A001542(n)/2.
%F A001109 a(n) = sqrt((A001541(n)^2-1)/8) (cf. Richardson comment).
%F A001109 a(n) = 3*a(n-1) + sqrt(8*a(n-1)^2+1). - _R. J. Mathar_, Oct 09 2000
%F A001109 a(n) = A000129(n)*A001333(n) = A000129(n)*(A000129(n)+A000129(n-1)) = ceiling(A001108(n)/sqrt(2)). - _Henry Bottomley_, Apr 19 2000
%F A001109 a(n) ~ (1/8)*sqrt(2)*(sqrt(2) + 1)^(2*n). - Joe Keane (jgk(AT)jgk.org), May 15 2002
%F A001109 Limit_{n->infinity} a(n)/a(n-1) = 3 + 2*sqrt(2). - _Gregory V. Richardson_, Oct 05 2002
%F A001109 a(n) = ((3 + 2*sqrt(2))^n - (3 - 2*sqrt(2))^n) / (4*sqrt(2)). - _Gregory V. Richardson_, Oct 13 2002. Corrected for offset 0, and rewritten. - _Wolfdieter Lang_, Feb 10 2015
%F A001109 a(2*n) = a(n)*A003499(n). 4*a(n) = A005319(n). - Mario Catalani (mario.catalani(AT)unito.it), Mar 21 2003
%F A001109 a(n) = floor((3+2*sqrt(2))^n/(4*sqrt(2))). - _Lekraj Beedassy_, Apr 23 2003
%F A001109 a(-n) = -a(n). - _Michael Somos_, Apr 07 2003
%F A001109 For n >= 1, a(n) = Sum_{k=0..n-1} A001653(k). - _Charlie Marion_, Jul 01 2003
%F A001109 For n > 0, 4*a(2*n) = A001653(n)^2 - A001653(n-1)^2. - _Charlie Marion_, Jul 16 2003
%F A001109 For n > 0, a(n) = Sum_{k = 0..n-1}((2*k+1)*A001652(n-1-k)) + A000217(n). - _Charlie Marion_, Jul 18 2003
%F A001109 a(2*n+1) = a(n+1)^2 - a(n)^2. - _Charlie Marion_, Jan 12 2004
%F A001109 a(k)*a(2*n+k) = a(n+k)^2 - a(n)^2; e.g., 204*7997214 = 40391^2 - 35^2. - _Charlie Marion_, Jan 15 2004
%F A001109 For j < n+1, a(k+j)*a(2*n+k-j) - Sum_{i = 0..j-1} a(2*n-(2*i+1)) = a(n+k)^2 - a(n)^2. - _Charlie Marion_, Jan 18 2004
%F A001109 From _Paul Barry_, Feb 06 2004: (Start)
%F A001109 a(n) = A000129(2*n)/2;
%F A001109 a(n) = ((1+sqrt(2))^(2*n) - (1-sqrt(2))^(2*n))*sqrt(2)/8;
%F A001109 a(n) = Sum_{i=0..n} Sum_{j=0..n} A000129(i+j)*n!/(i!*j!*(n-i-j)!)/2. (End)
%F A001109 E.g.f.: exp(3*x)*sinh(2*sqrt(2)*x)/(2*sqrt(2)). - _Paul Barry_, Apr 21 2004
%F A001109 A053141(n+1) + A055997(n+1) = A001541(n+1) + a(n+1). - _Creighton Dement_, Sep 16 2004
%F A001109 a(n) = Sum_{k=0..n} binomial(2*n, 2*k+1)*2^(k-1). - _Paul Barry_, Oct 01 2004
%F A001109 a(n) = A001653(n+1) - A038723(n); (a(n)) = chuseq[J]( 'ii' + 'jj' + .5'kk' + 'ij' - 'ji' + 2.5e ), apart from initial term. - _Creighton Dement_, Nov 19 2004, modified by _Davide Colazingari_, Jun 24 2016
%F A001109 a(n+1) = Sum_{k=0..n} A001850(k)*A001850(n-k), self convolution of central Delannoy numbers. - _Benoit Cloitre_, Sep 28 2005
%F A001109 a(n) = 7*(a(n-1) - a(n-2)) + a(n-3), a(1) = 0, a(2) = 1, a(3) = 6, n > 3. Also a(n) = ( (1 + sqrt(2) )^(2*n) - (1 - sqrt(2) )^(2*n) ) / (4*sqrt(2)). - _Antonio Alberto Olivares_, Oct 23 2003
%F A001109 a(n) = 5*(a(n-1) + a(n-2)) - a(n-3). - _Mohamed Bouhamida_, Sep 20 2006
%F A001109 Define f(x,s) = s*x + sqrt((s^2-1)*x^2+1); f(0,s)=0. a(n) = f(a(n-1),3), see second formula. - _Marcos Carreira_, Dec 27 2006
%F A001109 The perfect median m(n) can be expressed in terms of the Pell numbers P() = A000129() by m(n) = P(n + 2) * (P(n + 2) + (P(n + 1)) for n >= 0. - Winston A. Richards (ugu(AT)psu.edu), Jun 11 2007
%F A001109 For k = 0..n, a(2*n-k) - a(k) = 2*a(n-k)*A001541(n). Also, a(2*n+1-k) - a(k) = A002315(n-k)*A001653(n). - _Charlie Marion_, Jul 18 2007
%F A001109 [A001653(n), a(n)] = [1,4; 1,5]^n * [1,0]. - _Gary W. Adamson_, Mar 21 2008
%F A001109 a(n) = Sum_{k=0..n-1} 4^k*binomial(n+k,2*k+1). - _Paul Barry_, Apr 20 2009
%F A001109 a(n+1)^2 - 6*a(n+1)*a(n) + a(n)^2 = 1. - _Charlie Marion_, Dec 14 2010
%F A001109 a(n) = A002315(m)*A011900(n-m-1) + A001653(m)*A001652(n-m-1) - a(m) = A002315(m)*A053141(n-m-1) + A001653(m)*A046090(n-m-1) + a(m) with m < n; otherwise a(n) = A002315(m)*A053141(m-n) - A001653(m)*A011900(m-n) + a(m) = A002315(m)*A053141(m-n) - A001653(m)*A046090(m-n) - a(m) = (A002315(n) - A001653(n))/2. - _Kenneth J Ramsey_, Oct 12 2011
%F A001109 16*a(n)^2 + 1 = A056771(n). - _James R. Buddenhagen_, Dec 09 2011
%F A001109 A010054(A000290(a(n))) = 1. - _Reinhard Zumkeller_, Dec 17 2011
%F A001109 In general, a(n+k)^2 - A003499(k)*a(n+k)*a(n) + a(n)^2 = a(k)^2. - _Charlie Marion_, Jan 11 2012
%F A001109 a(n+1) = Sum_{k=0..n} A101950(n,k)*5^k. - _Philippe Deléham_, Feb 10 2012
%F A001109 PSUM transform of a(n+1) is A053142. PSUMSIGN transform of a(n+1) is A084158. BINOMIAL transform of a(n+1) is A164591. BINOMIAL transform of A086347 is a(n+1). BINOMIAL transform of A057087(n-1). - _Michael Somos_, May 11 2012
%F A001109 a(n+k) = A001541(k)*a(n) + sqrt(A132592(k)*a(n)^2 + a(k)^2). Generalizes formula dated Oct 09 2000. - _Charlie Marion_, Nov 27 2012
%F A001109 a(n) + a(n+2*k) = A003499(k)*a(n+k); a(n) + a(n+2*k+1) = A001653(k+1)*A002315(n+k). - _Charlie Marion_, Nov 29 2012
%F A001109 From _Peter Bala_, Dec 23 2012: (Start)
%F A001109 Product_{n >= 1} (1 + 1/a(n)) = 1 + sqrt(2).
%F A001109 Product_{n >= 2} (1 - 1/a(n)) = (1/3)*(1 + sqrt(2)). (End)
%F A001109 G.f.: G(0)*x/(2-6*x), where G(k) = 1 + 1/(1 - x*(8*k-9)/( x*(8*k-1) - 3/G(k+1) )); (continued fraction). - _Sergei N. Gladkovskii_, Aug 12 2013
%F A001109 G.f.: H(0)*x/2, where H(k) = 1 + 1/( 1 - x*(6-x)/(x*(6-x) + 1/H(k+1) )); (continued fraction). - _Sergei N. Gladkovskii_, Feb 18 2014
%F A001109 a(n) = (a(n-1)^2 - a(n-3)^2)/a(n-2) + a(n-4) for n > 3. - _Patrick J. McNab_, Jul 24 2015
%F A001109 a(n-k)*a(n+k) + a(k)^2 = a(n)^2, a(n+k) + a(n-k) = A003499(k)*a(n), for n >= k >= 0. - _Alexander Samokrutov_, Sep 30 2015
%F A001109 Dirichlet g.f.: (PolyLog(s,3+2*sqrt(2)) - PolyLog(s,3-2*sqrt(2)))/(4*sqrt(2)). - _Ilya Gutkovskiy_, Jun 27 2016
%F A001109 4*a(n)^2 - 1 = A278310(n) for n > 0. - _Bruno Berselli_, Nov 24 2016
%F A001109 From _Klaus Purath_, Jan 18 2020: (Start)
%F A001109 a(n) = (a(n-3) + a(n+3))/198.
%F A001109 a(n) = Sum_{i=1..n} A001653(i), n>=1.
%F A001109 a(n) = sinh( 2 * n * arccsch(1) ) / ( 2 * sqrt(2) ). - _Federico Provvedi_, Feb 01 2021
%F A001109 (End)
%F A001109 a(n) = A002965(2*n)*A002965(2*n+1). - _Jon E. Schoenfield_, Jan 08 2022
%F A001109 a(n) = A002965(4*n)/2. - _Gerry Martens_, Jul 14 2023
%F A001109 a(n) = Sum_{k = 0..n-1} (-1)^(n+k+1)*binomial(n+k, 2*k+1)*8^k. - _Peter Bala_, Jul 17 2023
%e A001109 G.f. = x + 6*x^2 + 35*x^3 + 204*x^4 + 1189*x^5 + 6930*x^6 + 40391*x^7 + ...
%e A001109 6 is in the sequence since 6^2 = 36 is a triangular number: 36 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8. - _Michael B. Porter_, Jul 02 2016
%p A001109 a[0]:=1: a[1]:=6: for n from 2 to 26 do a[n]:=6*a[n-1]-a[n-2] od: seq(a[n],n=0..26); # _Emeric Deutsch_
%p A001109 with (combinat):seq(fibonacci(2*n,2)/2, n=0..20); # _Zerinvary Lajos_, Apr 20 2008
%t A001109 Transpose[NestList[Flatten[{Rest[#],ListCorrelate[{-1,6},#]}]&, {0,1}, 30]][[1]]  (* _Harvey P. Dale_, Mar 23 2011 *)
%t A001109 CoefficientList[Series[x/(1-6x+x^2),{x,0,30}],x]  (* _Harvey P. Dale_, Mar 23 2011 *)
%t A001109 LinearRecurrence[{6, -1}, {0, 1}, 50] (* _Vladimir Joseph Stephan Orlovsky_, Feb 12 2012 *)
%t A001109 a[ n_]:= ChebyshevU[n-1, 3]; (* _Michael Somos_, Sep 02 2012 *)
%t A001109 Table[Fibonacci[2n, 2]/2, {n, 0, 20}] (* _Vladimir Reshetnikov_, Sep 16 2016 *)
%t A001109 TrigExpand@Table[Sinh[2 n ArcCsch[1]]/(2 Sqrt[2]), {n, 0, 10}] (* _Federico Provvedi_, Feb 01 2021 *)
%o A001109 (PARI) {a(n) = imag((3 + quadgen(32))^n)}; /* _Michael Somos_, Apr 07 2003 */
%o A001109 (PARI) {a(n) = subst( poltchebi( abs(n+1)) - 3 * poltchebi( abs(n)), x, 3) / 8}; /* _Michael Somos_, Apr 07 2003 */
%o A001109 (PARI) {a(n) = polchebyshev( n-1, 2, 3)}; /* _Michael Somos_, Sep 02 2012 */
%o A001109 (PARI) is(n)=ispolygonal(n^2,3) \\ _Charles R Greathouse IV_, Nov 03 2016
%o A001109 (Sage) [lucas_number1(n,6,1) for n in range(27)] # _Zerinvary Lajos_, Jun 25 2008
%o A001109 (Sage) [chebyshev_U(n-1,3) for n in (0..20)] # _G. C. Greubel_, Dec 23 2019
%o A001109 (Haskell)
%o A001109 a001109 n = a001109_list !! n :: Integer
%o A001109 a001109_list = 0 : 1 : zipWith (-)
%o A001109    (map (* 6) $ tail a001109_list) a001109_list
%o A001109 -- _Reinhard Zumkeller_, Dec 17 2011
%o A001109 (Magma) [n le 2 select n-1 else 6*Self(n-1)-Self(n-2): n in [1..30]]; // _Vincenzo Librandi_, Jul 25 2015
%o A001109 (GAP) a:=[0,1];; for n in [3..25] do a[n]:=6*a[n-1]-a[n-2]; od; a; # _Muniru A Asiru_, Dec 18 2018
%Y A001109 Cf. A000217, A000290, A001108, A001542, A001653, A001850, A002315, A002965, A278310.
%Y A001109 Chebyshev sequence U(n, m): A000027 (m=1), A001353 (m=2), this sequence (m=3), A001090 (m=4), A004189 (m=5), A004191 (m=6), A007655 (m=7), A077412 (m=8), A049660 (m=9), A075843 (m=10), A077421 (m=11), A077423 (m=12), A097309 (m=13), A097311 (m=14), A097313 (m=15), A029548 (m=16), A029547 (m=17), A144128 (m=18), A078987 (m=19), A097316 (m=33).
%Y A001109 Cf. A323182.
%K A001109 nonn,easy,nice
%O A001109 0,3
%A A001109 _N. J. A. Sloane_
%E A001109 Additional comments from _Wolfdieter Lang_, Feb 10 2000
%E A001109 Duplication of a formula removed by _Wolfdieter Lang_, Feb 10 2015

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