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Revision History for A373627 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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Expansion of 1 / ( (1 - 8*x^4) * (1 - x/(1 - 8*x^4)^(1/4)) ).
(history; published version)
#10 by Michael De Vlieger at Tue Jun 11 15:49:34 EDT 2024
STATUS

reviewed

approved

#9 by Hugo Pfoertner at Tue Jun 11 15:46:33 EDT 2024
STATUS

proposed

reviewed

#8 by Seiichi Manyama at Tue Jun 11 12:35:56 EDT 2024
STATUS

editing

proposed

#7 by Seiichi Manyama at Tue Jun 11 12:33:48 EDT 2024
FORMULA

a(4*n) = 9^n for n > = 0.

#6 by Seiichi Manyama at Tue Jun 11 12:25:07 EDT 2024
FORMULA

a(4*n) = 9^n for n > 0.

a(n) = Sum_{k=0..floor(n/4)} 8^k * binomial(n/4,k).

a(n) == 1 (mod 2).

#5 by Seiichi Manyama at Tue Jun 11 12:24:27 EDT 2024
DATA

1, 1, 1, 1, 9, 11, 13, 15, 81, 109, 141, 177, 729, 1041, 1429, 1901, 6561, 9759, 13981, 19419, 59049, 90483, 133893, 192327, 531441, 832911, 1264173, 1865539, 4782969, 7628799, 11816853, 17828163, 43046721, 69620541, 109646397, 168500385, 387420489, 633634769

#4 by Seiichi Manyama at Tue Jun 11 12:23:56 EDT 2024
PROG

(PARI) a(n) = sum(k=0, n\4, 8^k*binomial(n/4, k));

CROSSREFS
#3 by Seiichi Manyama at Tue Jun 11 12:18:27 EDT 2024
CROSSREFS

Cf. A373509.

#2 by Seiichi Manyama at Tue Jun 11 12:18:11 EDT 2024
NAME

allocated for Seiichi Manyama

Expansion of 1 / ( (1 - 8*x^4) * (1 - x/(1 - 8*x^4)^(1/4)) ).

DATA

1, 1, 1, 1, 9, 11, 13, 15, 81, 109, 141, 177, 729, 1041, 1429, 1901, 6561, 9759, 13981, 19419, 59049, 90483, 133893, 192327

OFFSET

0,5

KEYWORD

allocated

nonn

AUTHOR

Seiichi Manyama, Jun 11 2024

STATUS

approved

editing

#1 by Seiichi Manyama at Tue Jun 11 12:18:11 EDT 2024
NAME

allocated for Seiichi Manyama

KEYWORD

allocated

STATUS

approved