LINKS
Robert Israel, <a href="/A377045/b377045_1.txt">Table of n, a(n) for n = 1..153</a>
Discussion
Fri Nov 15
09:06
OEIS Server: Installed first b-file as b377045.txt.
LINKS
Robert Israel, <a href="/A377045/b377045_1.txt">Table of n, a(n) for n = 1..153</a>
MAPLE
R:= NULL: count:= 0:
for i from 1 while count < 30 do
p:= (i+1)^3 - i^3;
if isprime(p) then count:= count+1; v:= combinat:-numbpart(p); R:= R, v; fi
od:
R; # Robert Israel, Nov 14 2024
Discussion
Wed Oct 16
21:29
N. J. A. Sloane: [Annoucement: The Sequence Fans Mailing List is now a Google Group: Sign into Google, go to https://groups.google.com/g/seqfan, click "Join this group" - Neil Sloane]
COMMENTS
The next term a(13)=~1.49910*10^43 is too large to include.
a(14)=~1.17667*10^45.
Discussion
Tue Oct 15
16:59
Alois P. Heinz: they are not too large but data section is full ...
Discussion
Mon Oct 14
05:55
Joerg Arndt: What can we learn here what is not already i in A000041?
Tue Oct 15
16:19
Paul F. Marrero Romero: First of all, I apologise for the delay in responding, Mr Arndt. Well, I think that this sequence can be useful, because each Cuban prime can be directly related to the number of ways that this prime can be expressed as a sum of positive integers, and avoid taking on count other integers that are not Cuban primes, for which we have A000041 instead. Also, I think this might give some insight into how these partitions behave in relation to other classes of primes.
Regards.
COMMENTS
Number of partitions of primes p such that p=(3*k^2 + 1 )/4 for some integer k (A121259).
MATHEMATICA
PartitionsP[Select[Table[(3k^2 + 1)/4, {k, 50}], PrimeQ]]