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Revision History for A369485 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Expansion of (1/x) * Series_Reversion( x / ((1+x)^2 * (1+x+x^3)^2) ).
(history; published version)
#11 by Michel Marcus at Wed Jan 24 05:56:58 EST 2024
STATUS

reviewed

approved

#10 by Joerg Arndt at Wed Jan 24 02:04:45 EST 2024
STATUS

proposed

reviewed

#9 by Seiichi Manyama at Wed Jan 24 02:03:39 EST 2024
STATUS

editing

proposed

#8 by Seiichi Manyama at Tue Jan 23 23:46:31 EST 2024
FORMULA

a(n) = (1/(n+1)) * Sum_{k=0..floor(n/3)} binomial(2*n+2,k) * binomial(4*n-k+4,n-3*k).

#7 by Seiichi Manyama at Tue Jan 23 23:14:20 EST 2024
CROSSREFS
#6 by Seiichi Manyama at Tue Jan 23 23:11:33 EST 2024
PROG

(PARI) my(N=30, x='x+O('x^N)); Vec(serreverse(x/((1+x)^2*(1+x+x^3)^2))/x)

#5 by Seiichi Manyama at Tue Jan 23 23:03:15 EST 2024
DATA

1, 4, 22, 142, 1007, 7590, 59683, 484112, 4021061, 34029532, 292373296, 2543542676, 22360917140, 198341377680, 1772860026933, 15952960500612, 144397901220980, 1313835276189792, 12009823111155481, 110240431974732436, 1015727265740887873

#4 by Seiichi Manyama at Tue Jan 23 22:56:21 EST 2024
LINKS

<a href="/index/Res#revert">Index entries for reversions of series</a>

#3 by Seiichi Manyama at Tue Jan 23 22:54:01 EST 2024
PROG

(PARI) a(n, s=3, t=2, u=2) = sum(k=0, n\s, binomial(t*(n+1), k)*binomial((t+u)*(n+1)-k, n-s*k))/(n+1);

#2 by Seiichi Manyama at Tue Jan 23 22:51:13 EST 2024
NAME

allocated for Seiichi Manyama

Expansion of (1/x) * Series_Reversion( x / ((1+x)^2 * (1+x+x^3)^2) ).

DATA

1, 4, 22, 142, 1007, 7590, 59683, 484112, 4021061, 34029532, 292373296, 2543542676, 22360917140, 198341377680, 1772860026933, 15952960500612

OFFSET

0,2

KEYWORD

allocated

nonn

AUTHOR

Seiichi Manyama, Jan 23 2024

STATUS

approved

editing