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Simon Strandgaard, <a href="/A347342/a347342.png">TITLE FOR LINKPlot of 1000 terms</a>
Simon Strandgaard, <a href="/A347342/a347342.png">TITLE FOR LINK</a>
(PARI) a(n) = prime(n) % floor(prime(n) / n); (Ruby) require 'prime'
(Ruby) require 'prime'
allocated for Simon Strandgaard
a(n) = prime(n) mod floor(prime(n) / n).
0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 2, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 1, 2, 1, 2, 3, 3, 1, 3, 1, 3, 1, 3, 3, 1, 3, 1, 3, 1, 1, 3, 3, 3, 3, 1, 1, 3, 1, 3, 1, 3, 1, 3, 1, 1, 3, 1, 3, 3, 1, 1, 3, 1, 2, 1, 1, 3, 2, 3, 4, 3, 4, 2, 1, 4, 4, 1, 1, 3, 4, 3
1,13
a(1) = 2 mod floor( 2 / 1) = 2 mod 2 = 0,
a(2) = 3 mod floor( 3 / 2) = 3 mod 1 = 0,
a(3) = 5 mod floor( 5 / 3) = 5 mod 1 = 0,
a(4) = 7 mod floor( 7 / 4) = 7 mod 1 = 0,
a(5) = 11 mod floor(11 / 5) = 11 mod 2 = 1.
(PARI) a(n) = prime(n) % floor(prime(n) / n); (Ruby) require 'prime'
values = []
Prime.first(30).each_with_index do |prime, i|
values << prime % (prime/(i+1))
end
p values
allocated
nonn
Simon Strandgaard, Aug 27 2021
approved
editing
allocated for Simon Strandgaard
allocated
approved