editing
proposed
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editing
proposed
Smallest a(n) such that the product P = [a(n)*first digit of a(n)] is the smallest one strictly bigger than the previous one, with a(1) = 1 and no duplicate terms.
1, 2, 3, 10, 11, 12, 13, 14, 15, 4, 17, 18, 19, 5, 6, 20, 21, 22, 23, 24, 7, 25, 26, 27, 28, 29, 8, 9, 30, 31, 32, 33, 100, 101, 34, 103, 104, 35, 106, 107, 36, 109, 110, 37, 112, 113, 38, 115, 116, 39, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 40, 161, 162, 163, 41, 165, 166, 167, 42, 169, 170, 171, 43, 173, 174, 175, 44
We see in the Example section that P is the smallest possible product strictly bigger than the previous one and not leading to a contradiction.
Jean-Marc Falcoz, <a href="/A301382/b301382.txt">Table of n, a(n) for n = 1..9999</a>
allocated for Eric Angelini Smallest a(n) such that the product P = [a(n)*first digit of a(n)] is the smallest one strictly bigger than the previous one, with a(1) = 1 and no duplicate terms.
1, 2, 3, 10, 11, 12, 13, 14, 15, 4, 17, 18, 19, 5, 6, 20, 21, 22, 23, 24, 7, 25, 26, 27, 28, 29, 8, 9, 30, 31, 32, 33, 100, 101, 34, 103, 104, 35, 106, 107, 36, 109, 110, 37, 112, 113, 38, 115, 116, 39, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 40, 161, 162, 163, 41, 165, 166, 167, 42, 169, 170, 171, 43, 173, 174, 175, 44
1,2
We see in the Example section that P is the smallest possible product strictly bigger than the previous one and not leading to a contradiction.
a(1) * [the first digit of a(1)] = 1 * 1 = P = 1
a(2) * [the first digit of a(2)] = 2 * 2 = P = 4
a(3) * [the first digit of a(3)] = 3 * 3 = P = 9
a(4) * [the first digit of a(4)] = 10 * 1 = P = 10
a(5) * [the first digit of a(5)] = 11 * 1 = P = 11
a(6) * [the first digit of a(6)] = 12 * 1 = P = 12
a(7) * [the first digit of a(7)] = 13 * 1 = P = 13
a(8) * [the first digit of a(8)] = 14 * 1 = P = 14
a(9) * [the first digit of a(9)] = 15 * 1 = P = 15
a(10) * [the first digit of a(10)] = 4 * 4 = P = 16
a(11) * [the first digit of a(11)] = 17 * 1 = P = 17
Etc.
allocated
nonn,base
Eric Angelini and Jean-Marc Falcoz, Mar 20 2018
approved
editing
allocated for Eric Angelini
allocated
approved