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Revision History for A297443 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

newer changes | Showing entries 11-13
a(n) = a(n-1) + 2*a(n-2) - 2*a(n-3) + 3*a(n-4) - 3*a(n-5), where a(0) = 1, a(1) = 3, a(2) = 6, a(3) = 11, a(4) = 20, a(5) = 33.
(history; published version)
#3 by Clark Kimberling at Sun Jan 21 08:07:59 EST 2018
FORMULA

a(n) = a(n-1) + 2*a(n-2) - 2*a(n-3) + 3*a(n-4) - 3*a(n-5), where a(0) = 1, a(1) = 3, a(2) = 6, a(3) = 11, a(4) = 20, a(5) = 33.

G.f.: (3 + 3 x - x^2 + 3 x^3 - 6 x^4)/(1 - x - 2 x^2 + 2 x^3 - 3 x^4 +

3 x^5)

#2 by Clark Kimberling at Sun Jan 21 07:56:48 EST 2018
NAME

allocated for Clark Kimberling

a(n) = a(n-1) + 2*a(n-2) - 2*a(n-3) + 3*a(n-4) - 3*a(n-5), where a(0) = 1, a(1) = 3, a(2) = 6, a(3) = 11, a(4) = 20, a(5) = 33.

DATA

1, 3, 6, 11, 20, 33, 60, 101, 182, 303, 546, 911, 1640, 2733, 4920, 8201, 14762, 24603, 44286, 73811, 132860, 221433, 398580, 664301, 1195742, 1992903, 3587226, 5978711, 10761680, 17936133, 32285040, 53808401, 96855122, 161425203, 290565366, 484275611

OFFSET

0,2

COMMENTS

Conjecture: a(n) = least positive whose base-3 total variation is n; see A297440.

LINKS

Clark Kimberling, <a href="/A297443/b297443.txt">Table of n, a(n) for n = 0..1000</a>

<a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (1,2,-2,3,-3)

FORMULA

If n = (1 mod 4) or n = (1 mod 4), then a(n) = 3*a(n-2); otherwise, a(n) = 3*a(n-2) + 2.

MATHEMATICA

Join[{1}, LinearRecurrence[{1, 2, -2, 3, -3}, {3, 6, 11, 20, 33}, 40]]

CROSSREFS

Cf. A297440.

KEYWORD

allocated

nonn,easy

AUTHOR

Clark Kimberling, Jan 21 2018

STATUS

approved

editing

#1 by Clark Kimberling at Sat Dec 30 10:01:29 EST 2017
NAME

allocated for Clark Kimberling

KEYWORD

allocated

STATUS

approved