The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A269232 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A269232

a(n) = (n + 1)*(6*n^2 + 15*n + 4)/2.
(history; published version)

#20 by Charles R Greathouse IV at Thu Sep 08 08:46:15 EDT 2022

PROG

(MAGMAMagma) [(n+1)*(6*n^2+15*n+4)/2: n in [0..40]]; // Vincenzo Librandi, Feb 22 2016

Discussion

Thu Sep 08

08:46

OEIS Server: https://oeis.org/edit/global/2944

#19 by Bruno Berselli at Thu Feb 25 03:43:35 EST 2016

STATUS

proposed

approved

#18 by Vaclav Kotesovec at Thu Feb 25 03:35:51 EST 2016

STATUS

editing

proposed

Discussion

Thu Feb 25

03:43

Bruno Berselli: ;)

#17 by Vaclav Kotesovec at Thu Feb 25 03:33:06 EST 2016

FORMULA

a(n) = Sum_{k>=0..n} (3*k + (3*k+1)*(3*k+2)) = Sum_{k>=0..n} (A008585(k) + A001504(k)).

Discussion

Thu Feb 25

03:35

Vaclav Kotesovec: I have checked this formula, but you have good eyes, Bruno!

#16 by Bruno Berselli at Thu Feb 25 03:20:18 EST 2016

FORMULA

a(n) = Sum_{k>=0} (3*k + (3*k+1)*(3*k+2)) = Sum_{k>=0} (A008585(k) + A001504(k)).

STATUS

reviewed

editing

Discussion

Thu Feb 25

03:23

Bruno Berselli: Ilya, what is "a(n) = Sum_{k>=0} (3*k + (3*k+1)*(3*k+2))"? "k>=0" ??

#15 by Vaclav Kotesovec at Thu Feb 25 03:18:17 EST 2016

STATUS

proposed

reviewed

#14 by Vaclav Kotesovec at Thu Feb 25 03:18:11 EST 2016

STATUS

editing

proposed

#13 by Vaclav Kotesovec at Thu Feb 25 03:17:16 EST 2016

MATHEMATICA

LinearRecurrence[{4, -6, 4, -1}, {2, 25, 87, 206}, 3839]

STATUS

proposed

editing

#12 by Ilya Gutkovskiy at Wed Feb 24 12:59:58 EST 2016

STATUS

editing

proposed

#11 by Ilya Gutkovskiy at Wed Feb 24 12:59:32 EST 2016

FORMULA

Sum_{n>=0} 1/a(n) = 0.594386299683851108573156407113696623548787861365289...