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Revision History for A228786 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Table of coefficients of the minimal polynomials of 2*sin(Pi/n), n >= 1.
(history; published version)
#27 by Michel Marcus at Sat Jun 01 09:58:05 EDT 2024
STATUS

reviewed

approved

#26 by Joerg Arndt at Sat Jun 01 09:37:13 EDT 2024
STATUS

proposed

reviewed

#25 by Jon E. Schoenfield at Sat Jun 01 09:27:00 EDT 2024
STATUS

editing

proposed

#24 by Jon E. Schoenfield at Sat Jun 01 09:26:50 EDT 2024
COMMENTS

s(n) := 2*sin(Pi/n) is, for n >= 2, the length ratio side/R of the regular n-gon inscribed in a circle of radius R. This algebraic number s(n), n >= 1, has the degree gamma(n) := A055035(n), and the row length of this table is gamma(n) + 1.

Thanks go to _Seppo Mustonen _, who asked a question about the square of the sum of all length lengths in the regular n-gon , which led to this computation of s(n) and its minimal polynomial.

FORMULA

ps(n,x) = Product_{k=0.. floor(c(2*n)/n) and gcd(k, c(2*n)) = 1} (x - 2*cos(2*Pi*k/c(2*n)), with c(2*n) = A178182(2*n), for n >= 1. There are gamma(n) = A055035(n) zeros. - Wolfdieter Lang, Oct 30 2019

STATUS

approved

editing

#23 by Michael De Vlieger at Thu Aug 05 21:45:12 EDT 2021
STATUS

proposed

approved

#22 by Jon E. Schoenfield at Thu Aug 05 21:23:09 EDT 2021
STATUS

editing

proposed

#21 by Jon E. Schoenfield at Thu Aug 05 21:23:06 EDT 2021
COMMENTS

The zeros of the row polynomials ps(n,x) are 2*cos(2*Pi*k/c(2*n))) for gcd(k, c(2*n)) = 1, where c(n) = A178182(n), and k from {0, ..., floor(c(2*n)/2)}, for n >= 1. The number of these solutions is gamma(n) = A055035(n). See the fromula formula section. This results from the zeros of the minimal polynomials of sin(2*Pi/n), with coefficients given in A181872/A181873. - Wolfdieter Lang, Oct 30 2019

STATUS

approved

editing

#20 by Alois P. Heinz at Fri Jun 19 11:25:38 EDT 2020
STATUS

proposed

approved

#19 by Michel Marcus at Fri Jun 19 11:24:27 EDT 2020
STATUS

editing

proposed

#18 by Michel Marcus at Fri Jun 19 11:24:22 EDT 2020
COMMENTS

The zeros of the row polynomials ps(n,x) are 2*cos(2*Pi*k/c(2*n))) for gcd(k, c(2*n)) = 1, where c(n) = A178182(n), and k from {0, ..., floor(c(2*n)/2)}, for n >= 1. The number of these solutions is gamma(n) = A055035(n). See the fromula section. This results from the zeros of the minimal polynomials of sin(2*Pi/n), with coeffcients coefficients given in A181872/A181873. - Wolfdieter Lang, Oct 30 2019

STATUS

approved

editing