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Revision History for A212960 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Number of (w,x,y) with all terms in {0,...,n} and |w-x| != |x-y|.
(history; published version)
#17 by Charles R Greathouse IV at Sat Jun 13 00:54:15 EDT 2015
LINKS

<a href="/index/Rec">Index to sequences with entries for linear recurrences with constant coefficients</a>, signature (3,-2,-2,3,-1).

Discussion
Sat Jun 13
00:54
OEIS Server: https://oeis.org/edit/global/2439
#16 by Charles R Greathouse IV at Fri Jun 12 15:33:21 EDT 2015
LINKS

<a href="/index/Rec#recLCC">Index to sequences with linear recurrences with constant coefficients</a>, signature (3,-2,-2,3,-1).

Discussion
Fri Jun 12
15:33
OEIS Server: https://oeis.org/edit/global/2437
#15 by Joerg Arndt at Sat Apr 05 13:23:48 EDT 2014
STATUS

reviewed

approved

#14 by Michel Marcus at Sat Apr 05 08:02:25 EDT 2014
STATUS

proposed

reviewed

#13 by Michel Marcus at Sat Apr 05 08:02:20 EDT 2014
STATUS

editing

proposed

#12 by Michel Marcus at Sat Apr 05 08:02:06 EDT 2014
FORMULA

a(n) = 3*a(n-1)-2*a(n-2)-2*a(n-3)+3*a(n-4)-a(n-5).

G.f.: f(x)/g(x), where f(x)=4x(1+x^2+x^3) and g(x)=(1+x)(1-x)^4.

and g(x)=(1+x)(1-x)^4.

a(n) = (4*n^3 + 6*n^2 + 4*n+1 - (-1)^n)/4. _- _Luce ETIENNE_, Apr 05 2014

STATUS

proposed

editing

Discussion
Sat Apr 05
08:02
Michel Marcus: thanks for the Apr
#11 by Christopher Hunt Gribble at Sat Apr 05 08:00:07 EDT 2014
STATUS

editing

proposed

#10 by Christopher Hunt Gribble at Sat Apr 05 07:59:58 EDT 2014
FORMULA

a(n)=(4*n^3+6*n^2+4*n+1-(-1)^n)/4. Luce ETIENNE, April Apr 05 2014

#9 by Christopher Hunt Gribble at Sat Apr 05 06:56:47 EDT 2014
FORMULA

a(n)=(4*n^3+6*n^2+4*n+1-(-1)^n)/4. Luce ETIENNE, April 05 2014

STATUS

approved

editing

Discussion
Sat Apr 05
06:57
Christopher Hunt Gribble: Submitted on behalf of Luce Etienne.
#8 by T. D. Noe at Tue Jun 12 17:29:47 EDT 2012
STATUS

proposed

approved