FORMULA
a(n) ~ (1+sqrt(2))^(n+1/2) * n^n / (2^(1/4) * exp(n)). - Vaclav Kotesovec, Feb 18 2017
a(n) ~ (1+sqrt(2))^(n+1/2) * n^n / (2^(1/4) * exp(n)). - Vaclav Kotesovec, Feb 18 2017
K. S. Brown, <a href="http://www.mathpages.com/home/kmath381.htm">Integer Sequences Related To PI</a> [broken link]
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a(n+2) = (2n+3) *a(n+1) + (n+1)^2 *a(n), a(0) = 1, a(1) = 1.
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