[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A360105
Numbers k such that sigma_2(k^2 + 1) == 0 (mod k).
2
1, 2, 5, 7, 13, 25, 34, 52, 89, 93, 100, 200, 233, 338, 610, 850, 915, 1028, 1352, 1508, 1918, 2105, 3918, 4181, 5540, 6396, 6728, 7250, 9282, 10100, 10132, 10946, 15507, 16609, 17125, 32708, 32776, 37107, 42568, 47770, 58218, 61230, 72125, 74948, 75025, 78608
OFFSET
1,2
COMMENTS
Conjecture: the sequence contains infinitely many Fibonacci numbers (see A360107).
For k < 10^7, we observe only 6 prime numbers in the sequence: {2, 5, 7, 13, 89, 233} including the Fibonacci numbers {2, 5, 13, 89, 233} and the Lucas number {7}.
LINKS
EXAMPLE
7 is in the sequence because the divisors of 7^2+1 = 50 are {1, 2, 5, 10, 25, 50}, and 1^2 + 2^2 + 5^2 + 10^2 + 25^2 + 50^2 = 3255 = 7*465 == 0 (mod 7).
MAPLE
filter:= k -> NumberTheory:-SumOfDivisors(k^2+1, 2) mod k = 0:
select(filter, [$1..10^5]); # Robert Israel, Feb 19 2024
MATHEMATICA
Select[Range[50000], Divisible[DivisorSigma[2, #^2+1], #]&]
PROG
(PARI) isok(k) = sigma(k^2 + 1, 2) % k == 0; \\ Michel Marcus, Jan 26 2023
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Lagneau, Jan 26 2023
STATUS
approved