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A367352
Analog of A121805, but starting with 8.
9
8, 97, 168, 250, 252, 274, 317, 390, 393, 427, 502, 527, 603, 639, 736, 804, 852, 880, 888, 977, 1048, 1129, 1220, 1221, 1232, 1253, 1284, 1325, 1376, 1437, 1508, 1589, 1680, 1681, 1692, 1713, 1744, 1785, 1836, 1897, 1968, 2050, 2052, 2074, 2116, 2178, 2260, 2262, 2284
OFFSET
1,1
COMMENTS
Contains 198104936410 terms, the last being 9999999999972.
LINKS
MATHEMATICA
b = 10; m = b - 1; a[1] = 8; a[n_] := a[n] = For[r = Mod[a[n - 1], b]; y = 0, y <= m, y++, If[y == IntegerDigits[#, b][[1]], Return[#]] &[a[n - 1] + b r + y]]; Array[a, 45] (* Michael De Vlieger, Nov 18 2023, after Jean-François Alcover at A121805 *)
PROG
(Python)
from itertools import islice
def agen(start=8): # generator of terms
an, y = start, 1
while y < 10:
yield an
an, y = an + 10*(an%10), 1
while y < 10:
if str(an+y)[0] == str(y):
an += y
break
y += 1
print(list(islice(agen(), 50))) # Michael S. Branicky, Nov 18 2023
CROSSREFS
Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.
Sequence in context: A338571 A317005 A002506 * A318012 A320398 A218451
KEYWORD
nonn,fini,base
AUTHOR
N. J. A. Sloane, Nov 17 2023
STATUS
approved