A327172 - OEIS

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A327172

If there is a divisor d of n such that phi(d)*d = n, then a(n) = d, otherwise a(n) = 0.

1, 2, 0, 0, 0, 3, 0, 4, 0, 0, 0, 6, 0, 0, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0, 0, 0, 0, 0, 0, 10, 0, 7, 0, 0, 0, 0, 0, 12, 0, 0, 0, 0, 0, 9, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 18, 0, 11, 0, 0, 0, 0, 0, 0, 0, 0, 0, 15

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OFFSET

1,2

COMMENTS

If such a divisor exists, it is necessarily unique. See Franz Vrabec's Dec 12 2012 comment in A002618.

Each natural number n > 0 occurs exactly once in this sequence, at position A002618(n).

LINKS

Antti Karttunen, Table of n, a(n) for n = 1..21000

Antti Karttunen, Data supplement: n, a(n) computed for n = 1..100000

FORMULA

a(A002618(n)) = n.

a(A082473(n)) = A194507(n).