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A293482
The number of 5th powers in the multiplicative group modulo n.
13
1, 1, 2, 2, 4, 2, 6, 4, 6, 4, 2, 4, 12, 6, 8, 8, 16, 6, 18, 8, 12, 2, 22, 8, 4, 12, 18, 12, 28, 8, 6, 16, 4, 16, 24, 12, 36, 18, 24, 16, 8, 12, 42, 4, 24, 22, 46, 16, 42, 4, 32, 24, 52, 18, 8, 24, 36, 28, 58, 16, 12, 6, 36, 32, 48, 4, 66, 32, 44, 24, 14, 24, 72, 36, 8, 36, 12, 24, 78, 32, 54, 8, 82, 24
OFFSET
1,3
COMMENTS
The size of the set of numbers j^5 mod n, gcd(j,n)=1, 1 <= j <= n.
A000010(n) / a(n) is another multiplicative integer sequence.
LINKS
Samer Seraj, Counting general power residues, Not. Numb. Th. Discr. Math. 28 (4) (2022) 730-743.
FORMULA
Conjecture: a(2^e) = 1 for e <= 1; a(2^e) = 2^(e-1) for e >= 1; a(5)=4; a(5^e) = 4*5^(e-2) for e > 1; a(p^e) = (p-1)*p^(e-1) for p == {2,3,4} (mod 5); a(p^e) = (p-1)*p^(e-1)/5 for p == 1 (mod 5). - R. J. Mathar, Oct 13 2017
a(n) = A000010(n)/A319099(n). This implies that the conjecture above is true. - Jianing Song, Nov 10 2019
MAPLE
A293482 := proc(n)
local r, j;
r := {} ;
for j from 1 to n do
if igcd(j, n)= 1 then
r := r union { modp(j &^ 5, n) } ;
end if;
end do:
nops(r) ;
end proc:
seq(A293482(n), n=1..120) ;
MATHEMATICA
a[n_] := Module[{r, j}, r = {}; For[j = 1, j <= n, j++, If[GCD[j, n] == 1, r = r ~Union~ {PowerMod[j, 5, n]}] ]; Length[r]];
Table[a[n], {n, 1, 120}] (* Jean-François Alcover, Feb 14 2023, after R. J. Mathar *)
f[p_, e_] := (p - 1)*p^(e - 1)/If[Mod[p, 5] == 1, 5, 1]; f[2, e_] := 2^(e - 1); f[2, 1] = 1; f[5, e_] := 4*5^(e-2); f[5, 1] = 4; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Aug 10 2023 *)
CROSSREFS
The number of k-th powers in the multiplicative group modulo n: A046073 (k=2), A087692 (k=3), A250207 (k=4), this sequence (k=5), A293483 (k=6), A293484 (k=7), A293485 (k=8).
Sequence in context: A262550 A077651 A004085 * A086296 A096504 A277906
KEYWORD
nonn,mult
AUTHOR
R. J. Mathar, Oct 10 2017
STATUS
approved