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Positions of 0 in A288257; complement of A288259.
3

%I #4 Jun 09 2017 19:38:46

%S 1,2,4,6,7,8,10,11,12,13,15,16,18,19,20,21,23,24,25,27,29,30,31,32,34,

%T 36,37,38,39,41,42,43,45,47,48,49,50,52,53,55,56,57,59,60,61,62,64,65,

%U 66,68,70,71,72,74,75,76,77,79,80,81,83,85,86,87,88,90

%N Positions of 0 in A288257; complement of A288259.

%C Conjecture: a(n)/n-> 1.36..., and if m denotes this number, then -1 < m - a(n)/n < 1 for n >= 1.

%H Clark Kimberling, <a href="/A288258/b288258.txt">Table of n, a(n) for n = 1..10000</a>

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "0010", "1" -> "100"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[11]] - 48 (* A288257 *)

%t Flatten[Position[st, 0]] (* A288258 *)

%t Flatten[Position[st, 1]] (* A288259 *)

%Y Cf. A288257, A288259.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, Jun 09 2017